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MissTica
2 years ago
12

Sixty-eight percent of adults in a certain country believe that life on other planets is plausible. You randomly select five adu

lts and ask them whether they believe that life on other planets is plausible. The random variable represents the number of adults who believe that life on other planets is plausible. Find the mean, variance, and standard deviation of the binomial distribution for the random variable. Interpret the results.
Mathematics
1 answer:
Pavlova-9 [17]2 years ago
3 0

Answer:

Mean = 3.4

Variance = 1.088

Standard deviation = 1.0431

Step-by-step explanation:

P=0.68\\ \\N=5

The mean of a binomial distribution with parameters N (the number of trials) and p (the probability of success for each trial) is m=N\cdot p

Thus,

m=5\cdot 0.68=3.4

The variance of the binomial distribution is s^2=Np(1-p), where s^2​​ is the variance of the binomial distribution, so

s^2=5\cdot 0.68\cdot (1-0.68)=3.4\cdot 0.32=1.088

The standard deviation s is the square root of the variance s^2, so

s=\sqrt{1.088}\approx 1.0431

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A sample with a sample proportion of 0.4 and which of the following sizes will produce the widest 95% confidence interval when e
Fed [463]

Answer:

C. 50

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The higher the margin of error, the wider an interval is.

As the sample size increases, the margin of error decreases. If we want a widest possible interval, we should select the smallest possible confidence interval.

So the correct answer is:

C. 50

6 0
2 years ago
a school district requires all graduating seniors to take a mathematics test. This year, the rest scores were approximately norm
Klio2033 [76]
A score of 85 would be 1 standard deviation from the mean, 74.  Using the 68-95-99.7 rule, we know that 68% of normally distributed data falls within 1 standard deviation of the mean.  This means that 100%-68% = 32% of the data is either higher or lower.  32/2 = 16% of the data will be higher than 1 standard deviation from the mean and 16% of the data will be lower than 1 standard deviation from the mean.  This means that 16% of the graduating seniors should have a score above 85%.
3 0
2 years ago
Triangle J K L is shown. Angle J K L is a right angle. An altitude is drawn from point K to point M on side L J to form a right
KiRa [710]

Answer:

3\sqrt{5}\ units

Step-by-step explanation:

<u>Theorem 1:</u> The height of right triangle drawn from the right angle to the hypotenuse divides the hypotenuse into two segments. The length of the altitude is the geometric mean of these two segments. Hence,

KM^2=ML\cdot MJ\\ \\6^2=ML\cdot 3\\ \\3ML=36\\ \\ML=12\ units

<u>Theorem 2:</u> In a right triangle, the altitude drawn from the right angle to the hypotenuse divides the hypotenuse into two segments. The length of each leg of the right triangle is the geometric mean of the lengths of the hypotenuse and the segment of the hypotenuse that is adjacent to the leg.

Thus,

KJ^2=MJ\cdot ML\\ \\KJ^2=3\cdot (3+12)\\ \\KJ^2=3\cdot 15\\ \\KJ^2=45\\ \\KJ=\sqrt{45}=3\sqrt{5}\ units

5 0
2 years ago
a total of 17100 seats are still available for the next hockey game.if 62% of the tickets are sold how many seats are in the are
BartSMP [9]
If 62% of the seats are sold; 

100-62= 38% seats still available. 

17100=38% seats available

17100/38= seats in 1%
450 seats

In 100%, 
450×100=450000 seats total. 

Hope I helped :) 
3 0
2 years ago
What is the numerical sum of the degree measures of ∠DEA and ∠AEB?
inessss [21]
The angles are supplementary, therefore totaling them at 180°.

And because I'm bored, I'll solve for x for you!

(x + 25) + (9x + 10) = 180
10x + 35 = 180
Subtract 35 from both sides.
10x = 145
Divide by 10 on both sides.
x = 14.5
3 0
2 years ago
Read 2 more answers
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