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2 years ago

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Linnea is renting a bike. It costs $4.50 per hour plus a $5 deposit. a. Draw a line to show the relationship between the number

of hours a bike is rented, x, and the total cost of renting a bike, y.

1 answer:

lana [24]2 years ago

3 0

Answer:

(see image)

Step-by-step explanation:

You might be interested in

3x2+3y2+2x-8=0<br><br> Find the center and radius

timofeeve [1]

Answer: Center: (0, 2) Radius: 2
I hope this helps! :)

3 0

1 year ago

A stadium has two sponsorship deals. Deal A had revenue of $100,000 and expense of $10,000. Deal B has revenue of $50,000 and ex

horsena [70]

Answer:

Deal A) 90% Profit ; Deal B) 60% Profit

Step-by-step explanation:

Multiple ways of solving this problem here is one way:

100k-10k = 90k(Revenue) : Then you make this as a percent by 100k then multiply it by 100.

100*((100,000-10,000)/100,000) = 90%

The same is true for the other equation:

100*((50,000-20,000)/50,000) = 60%

4 0

1 year ago

Read 2 more answers

The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po

Leona [35]

Answer:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

Step-by-step explanation:

Data given

Campus Sample size Mean Population deviation

1 330 33 8

2 310 31 7

$\bar X_{1}=33$ represent the mean for sample 1

$\bar X_{2}=31$ represent the mean for sample 2

$\sigma_{1}=8$ represent the population standard deviation for 1

$\sigma_{2}=7$ represent the population standard deviation for 2

$n_{1}=330$ sample size for the group 1

$n_{2}=310$ sample size for the group 2

$\alpha$ Significance level provided

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

P value

Since is a one right tailed test the p value would be:

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

5 0

2 years ago

Data sets A and B are dependent. Find sd.Assume that the paired data came from a population that is normally distributed.A. 1.73

marusya05 [52]

Complete question :

A : 2.7, 3.7, 5.6, 2.6, 2.7

B : 5.1, 4.0, 3.9, 3.8, 5.2

Data sets A and B are dependent. Find sd.Assume that the paired data came from a population that is normally distributed.A. 1.73B. 1.21C. 1.32D. 1.89

Answer: A.1.73

Step-by-step explanation:

Given the data:

A : 2.7, 3.7, 5.6, 2.6, 2.7

B : 5.1, 4.0, 3.9, 3.8, 5.2

Difference betweenA and B (A - B) :

Xd = (A - B) = - 2.4, -0.3, 1.7, - 1.2, - 2.5

Sum of (A - B) = Σ Xd = (-2.4 + (-0.3) + 1.7 + (-1.2) + (-2.5) = - 4. 7

Md = ΣXd / n = - 4.7 / 5 = - 0.94

Xd - Md = (-2.4 + 0.94), (-0.3 + 0.94), (1.7 + 0.94), (-1.2 + 0.94), (-2.5 + 0.94)

(Xd - Md) = - 1.46, 0.64, 2.64, - 0.26, - 1.56

(Xd - Md)^2 = (-1.46)^2 + 0.64^2 + 2.64^2 + (-0.26)^2 + (-1.56)^2

Σ(Xd - Md)^2 = (2.1316 + 0.4096 + 6.9696 + 0.0676 + 2.4336) = 12.012

Standard deviation = √[Σ(Xd - Md)^2 / (n-1)]

Standard deviation= √12.012 / 4

Standard deviation = 1.7329

Standard deviation= 1.73

3 0

2 years ago

Ralph is estimating the cost of concrete to build a slab. The slab will have a length of 12 feet, a width of 9 feet, and a thick

snow_lady [41]

Answer:

$20196

Step-by-step explanation:

12 × 9 × 6 = 648 cubic feet ( volume of slab )

3 feet to a yard

So 648 ÷ 3 = 216

Multiply this by 1.1 to add an extra 10%

237.6 Cubic Yards Needed

$85 × 237.6 = $ 20196

Hope this helps

4 0

1 year ago