Let C be the amount of compost
T be the amount of topsoil
Each compost cost = $25
Cost of C compost = 25C
Each topsoil cost = $15
Cost of T topsoil = 15T
Amount of compost + amount of topsoil = 10
C + T = 10 -------> Equation 1
cost of C compost + cost of T topsoil = 180
25C + 15T = 180 --------> equation 2
Solve the first equation for C
C + T = 10
C = 10 - T
Now plug it in second equation
25C + 15T = 180
25 ( 10 - T) +15T = 180
250 - 25T + 15T = 180 (combine like terms)
250 - 10 T = 180 (Subtract 250 on both sides)
-10T = 180 - 250
-10T = -70 ( divide by -10 on both sides)
T = 7
She purchased 7 cubic yards of topsoil .
Answer:
we have P(x) = mx + 1
Step-by-step explanation:
Allow me to revise your question for a better understanding:
<em>The pressure at sea level is 1 atmosphere and increases at a constant rate as depth increases. When Sydney dives to a depth of 23 meters, the pressure around her is 3.3 point, 3 atmospheres. The pressure p in atmospheres is a function of x, the depth in meters.</em>
My answer:
Given:
At O meter the the pressure is 1 (0, 1)
At 23 meters the the pressure is 3.3 (23, 3.3)
From that, we can form a linear equation with the standard form:
P(x) = mx + b (1)
The slope of (1) is:
<=> P(x) = 0.1x + b
Substitute the point (0, 1) into (1) we have:
1 = 0.1*0 + b
<=> b = 1
So we have the equation of this line will be: P(x) = mx + 1
Answer:
The standard form is 
Step-by-step explanation:
Given:

To Find :
standard form of 
Solution:
A polynomial is in standard form when its term of highest degree is first, its term of 2nd highest is 2nd etc.
In order to write any polynomial in standard form, you look at the degree of each term. You then write each term in order of degree, from highest to lowest, left to write.
Now lets check the degree of each term in the polynomial
The degree of 6x is 5
The degree of 8x is 1
The degree of 3x is 3
The degree of 7x is 7
Now rewrite the polynomial in the order of the degree, from highest to lowest

Angles RLN and MLK would be vertical angles.
Right. Vertical angles are formed when their
sides share the same lines. RL shares the same line with LM and NL shares the
same line with LK (see the attached diagram), so that means both angles form a vertical
pair.
Angles RLN and MLN would be vertical angles.
Wrong. They are linear pairs, because they
are adjacent and supplementary. Adjacent angles share a side – in this case,
LN. Supplementary angles sum 180°, which you can see is right because the other
sides (ML and RL) are in the same line. RLN and MLN sum the same as the size of
RLM, which is a line, so it’s 180°.
<span>
Angles RLN and KLM would be a linear pair. </span>
Wrong. They would be a vertical pair (see
definition of vertical pair in the first option). RL is opposed to LM and LN is
opposed to KL.
Angles RLN and KLN would be a linear pair.
Wrong. KLN is actually a line, so it’s actually
180°, so it can’t be a linear pair with KLN. Linear pairs sum 180°, which is
impossible because KLN itself is already 180°, so any sum will throw a higher
number.