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RUDIKE [14]
2 years ago
8

Ashley recently opened a store that uses only natural ingredients. She wants to advertise her products by distributing bags of s

amples in her neighborhood. It takes Ashley \dfrac{2}{3} 3 2 ​ start fraction, 2, divided by, 3, end fraction of a minute to prepare one bag. It takes each of her friends 75\%75%75, percent longer to prepare a bag. How many hours will it take Ashley and 444 of her friends to prepare 157515751575 bags of samples?
Mathematics
1 answer:
Elenna [48]2 years ago
3 0

I will rewrite the question for better understanding:

Ashley recently opened a store that uses only natural ingredients. She wants to advertise her products by distributing bags of samples in her neighborhood. It takes Ashley 2/3 of a minute to prepare one bag. It takes each of her friends 75% longer to prepare a bag. How many hours will it take Ashley and 4 of her friends to prepare 1575 bags of samples?

Answer:

  • <em><u>5.3 hours</u></em>

Explanation:

<u>1) Time it takes Ashley to preprate one bag: </u>

  • 2/3 min

<u>2) Time it takes each friend of Ashley: 75% more than 2/3 min</u>

  • 75% × 2/3 min = 0.75 × 2/3 min = 3/4 × 2/3 min= 2/4 min = 1/2 min = 0.5 min
  • 2/3 min + 1/2 min = 7/6 min

<u>3) Time it takes Ashley and the 4 friends working along to prepare one bag:</u>

  • Convert each time into a rate, since you can set that the total rate of Ashley along with her four friends is equal to the sum of each rate:

  • Rate of Ashley: 1 bag / (2/3) min = 3/2 bag/min

  • Rate of each friend: 1 bag / (7/6) min = 6/7 bag/min

  • Rate of Ashley and 4 friends = 3/2 bag/min + 4 × 6/7 bag/min = (3/2 +24/7) bag/min = 69/14 bag/min

<u>4) Time of prepare 1575 bags of samples:</u>

  • time = number of bags / number of bags per min = 1,575 bags / (69/14) bags/min = 319.56 min

<u>5) Convert minutes to hours:</u>

  • 356.56 min × 1 hour / 60 min = 5.3 hours
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2 years ago
Find the sum of the first 63 terms of –19, -13, -7 …
boyakko [2]

The Given Sequence is an Arithmetic Sequence with First term = -19

⇒ a = -19

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We know that Common difference is Difference of second term and first term.

⇒ Common Difference (d) = -13 + 19 = 6

We know that Sum of n terms is given by : S_n = \frac{n}{2}(2a + (n - 1)d)

Given n = 63 and we found a = -19 and d = 6

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\implies S_6_3 = \frac{63}{2}(-38 + (62)6)

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2 years ago
762,508 expanded form using exponents
r-ruslan [8.4K]

762,508 in expanded form using exponents is given as:

7 \times 10^5 + 6 \times 10^4 + 2 \times 10^3 + 5 \times 10^2 +0 \times 10^1 + 8 \times 10^0

<h3><u>Solution:</u></h3>

Given that we have to write 762, 508 in expanded form using exponents

Expanded form or expanded notation is a way of writing numbers to see the math value of individual digits

<h3><u>Write 762508 in Expanded form</u></h3>

Let us first find the place value of digits

Place value can be defined as the value represented by a digit in a number on the basis of its position in the number.

Place value of 7 = 700000

In 762508, 7 is in hundred-thousands place

Place value of 6 = 60000

In 762508, 6 is in ten-thousands place.

Place value of 2 = 2000

In 762508, 2 is in thousands place

Place value of 5 = 500

In 762508, 5 is in hundreds place

Place value of 0 = 0 x 10 = 0

In 762508, 0 is in tens place

Place value of 8 = 8

In 762508, 8 is in ones place

Therefore, the expanded form is given as:

700,000 + 60,000 + 2,000 + 500 + 0 + 8

<u><em>Using exponents we can write as,</em></u>

7 \times 10^5 + 6 \times 10^4 + 2 \times 10^3 + 5 \times 10^2 +0 \times 10^1 + 8 \times 10^0

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2 years ago
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