Round 545,999 to the nearest hundred thousand

it takes max 1.8 hours to walk home from work at a rate of 3.5km/h. how long would it take max to cover the same distance walkin

NikAS [45]

Time taken by Max to cover the same distance walking at 4.2 km/h is 1.5 hours

<h3>Solution:</h3>

Given it takes Max 1.8 hours to walk home from work at a rate of 3.5km/h

We have to find time taken by Max to cover the same distance walking at 4.2 km/h

The relation between speed and time is given as:

$speed = \frac{distance}{time}$

CASE 1:

It takes Max 1.8 hours to walk home from work at a rate of 3.5km/h

Let us first find the distance covered

Time taken = 1.8 hours and speed = 3.5 km/hr

$3.5 = \frac{distance}{1.8}\\\\distance = 3.5 \times 1.8 = 6.3$

Hence distance covered is 6.3 km

Now we have to find the time taken to cover same 6.3 km walking at 4.2 km\hr

$4.2 = \frac{6.3}{time taken}\\\\time taken = \frac{6.3}{4.2} = 1.5$

So time taken by Max to cover the same distance walking at 4.2 km/h is 1.5 hours

3 0

1 year ago

In 2014, 85 percent of households in the United States had a computer. For a randomly selected sample of 200 households in 2014,

DochEvi [55]

Answer:

The mean of C is 170 households

The standard deviation of C, is approximately 5 households

Step-by-step explanation:

The given parameters are;

The percentage of households in the United States that had a computer in 2014 = 85%

The size of the randomly selected sample in 2014, n = 200

The random variable representing the number of households that had a computer = C

Therefore, we have;

The probability of a household having a computer P = 85/100 = 0.85

Let

Therefore;

The mean (expected) number in the sample, μₓ, = E(x) = n × P is given as follows;

μₓ = 200 × 0.85 = 170

The mean of C = μₓ = 170

The variance, σ² = n × P × (1 - P) = 200 × 0.85 × (1 - 0.85) = 25.5

Therefore;

The standard deviation, σ = √(σ²) = √(25.5) ≈ 5.05

The standard deviation of C, σ ≈ 5 households (we round (down) to the nearest whole number)

7 0

2 years ago

Read 2 more answers

Tariq wrote the equation y=3.2x to represent the line of best fit for the data shown. Is his line a good representation for the

Setler79 [48]

Answer:

No

Step-by-step explanation:

The way to find the line of best fit by estimate is to have about half the points be above and below the line of best fit. In this case Tariq followed the first few points of the data but his estimate would be very off after 10 on the x axis. This would not accurately predict what the next data point could be.

6 0

1 year ago

Write v as a linear combination of u1, u2, and u3, if possible. (If not possible, enter IMPOSSIBLE.) v = (7, −14, −3, −4), u1 =

AlexFokin [52]

Answer:

IMPOSSIBLE

Step-by-step explanation:

8 0

2 years ago

Ben swims 50,000 yards per week in his practices. Given this amount of training, he will swim the 100-yard butterfly in 51.5

Elanso [62]

Answer:

MArginal productivity: $\frac{dt}{dL}=-0.0002$

We can interpret this as he will reduce his time an additional 0.0002 seconds for every additional yard he trains.

Step-by-step explanation:

The marginal productivy is the instant rate of change in the result for an increase in one unit of a factor.

In this case, the productivity is the time he last in the 100-yard. The factor is the amount of yards he train per week.

The marginal productivity can be expressed as:

$\frac{dt}{dL}$

where dt is the variation in time and dL is the variation in training yards.

We can not derive the function because it is not defined, but we can approximate with the last two points given:

$\frac{dt}{dL}\approx\frac{\Delta t}{\Delta L} =\frac{t_2-t_1}{L_2-L_1}=\frac{44.6-46.4}{70,000-60,000}=\frac{-2.0}{10,000}=-0.0002$

Then we can interpret this as he will reduce his time an additional 0.0002 seconds for every additional yard he trains.

This is an approximation that is valid in the interval of 60,000 to 70,000 yards of training.

6 0

1 year ago