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lukranit [14]
2 years ago
9

Light passes through a pair of very thin parallel slits. The resulting interference pattern is viewed far from the slits at vari

ous angles θ relative to the centerline coming outward from the midpoint between the slits. The central bright fringe is at θ=0∘. If the central bright fringe has intensity I0, what is the intensity of the next bright fringe on either side of it?
Physics
1 answer:
butalik [34]2 years ago
4 0

Answer:

Intensity of the next bright fringe will remain same.

Explanation:

The question is based on Young's double slit experiment, since its about bright fringe, the interference here is constructive.

Young's condition for constructive interference is given by:

dsin\theta = n\lambda

where,

d = slits distance from eachother or width of the slits

\lambda = wavelength

n = interferance order

Also, we know that in Young's experiment, the fringe intensity is given by:

I' = 4Icos^{2}\phi

where,

\phi = phase difference

Therefore, in absence of phase difference i.e., \phi = 0, the intensity of the next bright fringe will not change and it will remain same.

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Emmy kicks a soccer ball up at an angle of 45° over a level field. She watches the ball's trajectory and notices that it lands,
Elenna [48]

Let u be the initial velocity of the soccer ball at an angle of inclination of \theta_0 with the positive x-axis.

Given that:

\theta_0=45^{\circ}

The horizontal distance covered by the projectile=20 m

Time of flight, t_f=2 seconds

Acceleration due to gravity, g= 10 m/s^2 downward.

As "north" and "up" as the positive x ‑ and y ‑directions, respectively.

So, g= -10 m/s^2

As the acceleration due to gravity is in the vertical direction, so the horizontal component of the initial velocity remains unchanged.

The x-component of the initial velocity, u_x=u\cos\theta_0.

The horizontal distance covered by the projectile = u_x\times t_f

\Rightarrow u_x\times t_f=20

\Rightarrow u_x\times 2=20

\Rightarrow u_x=10 m/s

So, the horizontal component of the velocity is 10 m/s which is constant and the graph has been shown in the figure (i).

Now,  u\cos(45^{\circ})=10 [as u_x=u\cos\theta_0]

\Rightarrow u=10\sqrt{2} m/s.

The vertical component of the initial velocity,

u_y= u\sin\theta_0

\Rightarrow u_y=10\sqrt{2}\sin(45^{\circ})

\Rightarrow u_y=10 m/s

Let v be the vertical component of the velocity at any time instant t.

From the equation of motion,

v=u+at

where u: initial velocity, v: final velocity, a: constant acceleration, and t: time taken to change the velocity from u to v.

In this case, we have u=u_y, a= -10 m/s^2.

So at any time instant, t.

v=u_y+(-10)t

\Rightarrow v=10-10t

The vertical component of the velocity, v, is the function of time and related as v=10-10t.

This is a linear equation.

At 2 second, the vertical component of the velocity

v=10-10x2=-10 m/s.

The graph has been shown in figure (ii).

7 0
2 years ago
A noise level of 95 db is ______ than the lowest level at which hearing protection is required (85 db), and your exposure should
LUCKY_DIMON [66]
The answer to this question is "Greater than". As per the OSHA or Organizational Health and Health Organization, a noise level of 95 DB or decibels is greater than the lowest level at which hearing protection is required in 85 decibels and the person's exposure should be limited only to six hours or less than of it. 
3 0
2 years ago
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A Labrador retriever breeder needs to determine if three male pups who were born to Sadie, his black Labrador retriever, are the
Novosadov [1.4K]

Answer: The things we know are:

Sadie, the mother, is a black labrador.

Sam, the possible father, is a yellow labrador.

Discarding things such as a scientific indagation, the breeder could look for traits in the pups.

For example, yellow is recessive against black, so if the pups are yellow, there is probable that the father is Sam, none the less, if the pups are black there is also the possibility where Sam is the father, just in this case the color genes that the pups received are the ones of the mother.

A good starting point is looking at the color, the posture, and things like that.

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7 0
2 years ago
Jade and her roommate Jari commute to work each morning, traveling west on I-10. One morning Jade left for work at 6:45 A.M., bu
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Answer:

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Explanation:

The question requires to know who is traveling faster. This is done by comparing the gradients. The steeper the slope (high gradient), the faster the speed and vice versa.

From Jari's line, the starting point is (0, 0) and another point is (6, 7)

The gradient being change in y to change in x

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Change in x=6-0=6

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For Jade, first point is (0, 10) then another point is (6, 16)

Change in y=16-10=6

Change in x=6-0=6

Slope is 6/6=1

Clearly, 7/6 is greater than 6/6 or 1 hence Jari is faster than Jade

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12000 m/s = 12 km/s. Now to go 380000 km, it will take some time. How much time is given in the formula 12km/s. You go 12 kilometers every second. So you take \frac{380000km}{12km/s} and that gives you 31,666.666 seconds. 
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