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Rom4ik [11]
2 years ago
15

Jade and her roommate Jari commute to work each morning, traveling west on I-10. One morning Jade left for work at 6:45 A.M., bu

t Jari left 15 minutes later. Both drove at a constant speed. The following graphs show the distance (in miles) each of them has traveled on I-10 at time t (in minutes), where t = 0 is 7:00 A.M.

Physics
1 answer:
Veronika [31]2 years ago
3 0

Answer:

Jari

Explanation:

The question requires to know who is traveling faster. This is done by comparing the gradients. The steeper the slope (high gradient), the faster the speed and vice versa.

From Jari's line, the starting point is (0, 0) and another point is (6, 7)

The gradient being change in y to change in x

Change in y=7-0=7

Change in x=6-0=6

Slope is 7/6

For Jade, first point is (0, 10) then another point is (6, 16)

Change in y=16-10=6

Change in x=6-0=6

Slope is 6/6=1

Clearly, 7/6 is greater than 6/6 or 1 hence Jari is faster than Jade

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A stationary 1.67-kg object is struck by a stick. The object experiences a horizontal force given by F = at - bt2, where t is th
Usimov [2.4K]

Answer:

v_{f}  = 3289.8 m / s

Explanation:

This exercise can be solved using the definition of momentum

     I = ∫ F dt

Let's replace and calculate

     I = ∫ (at - bt²) dt

We integrate

      I = a t² / 2 - b t³ / 3

We evaluate between the lower limits I=0  for t = 0 s and higher I=I for t = 2.74 ms

      I = a (2,74² / 2- 0) - b (2,74³ / 3 -0)

      I = a 3,754 - b 6,857

We substitute the values ​​of a and b

      I = 1500 3,754 - 20 6,857

      I = 5,631 - 137.14

      I = 5493.9 N s

Now let's use the relationship between momentum and momentum

      I = Δp = m v_{f} - m v₀o

      I = m v_{f}  - 0

     v_{f}  = I / m

    v_{f}  = 5493.9 /1.67

    v_{f}  = 3289.8 m / s

5 0
1 year ago
The force sensor measures the force on the sensor due to the bumper, but the cart's momentum change arises from the force on the
Irina-Kira [14]

Answer:

Answered

Explanation:

1 and 3 are necessary

Every bit of force applied to the bumper will be transmitted to the cart EXCEPT for the force needed to accelerate the bumper. This is the net force on the bumper.

If the bumper was heavy then a significant amount of force might be needed to accelerate the bumper so the amount transmitted to the cart would be substantially reduced.

If the net force on the bumper is small then the amount transmitted to the cart is almost the entire force applied.

5 0
2 years ago
The table below shows data of sprints of animals that traveled 75 meters. At each distance marker, the animals' times were recor
mr_godi [17]

Answer:

Explanation:

Animal 1 because it takes 3s to go 25 meters 3.5s to go 50 meters and 5s to go 75 meters while the others take longer.

5 0
2 years ago
Read 2 more answers
Alex goes cruising on his dirt bike. He rides 700m north, 300m east, 400 m north, 600m west, 1200m south, 300m east and finally
Bess [88]

Find Displacement and Distance

displacement ...

north is 700+400+100 =1200m n

south=1200m

1200-1200=0


east is 300+300=600m

west is 600m

600-600=0

back at dtart. displ zero


distance is 700+ 300m + 400 m + 600m + 1200m + 300m + 100m  = 3600m


3 0
2 years ago
You throw a baseball straight up into the air with a speed of 24.5 m/s. How long does it take the baseball to reach its highest
galben [10]
Time=speed/acceleration
Gravitaional Acceleration=9.8 m/s^2
Speed=24.5 m/s
Time=24.5/9.8=2.5 s
3 0
2 years ago
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