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mixas84 [53]
2 years ago
14

Inspiratory capacity is ________. A. functional residual capacity B. air inspired after a tidal inhalation C. the total amount o

f air that can be inspired after a tidal expiration D. the total amount of exchangeable air
Computers and Technology
1 answer:
Sav [38]2 years ago
4 0

Answer:

C. the total amount of air that can be inspired after a tidal expiration

Explanation:

According to my research on studies conducted by biologists, I can say that based on their studies the Inspiratory Capacity is defined as the total amount of air that can be inspired after a tidal expiration. Tidal expiration means the amount of air that is expelled after taking a breath, which is calculated as an average of 500 ml at rest.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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The alternative to encapsulating security protocol (esp) is _________.
Lina20 [59]
The alternative to Encapsulating Security Protocol (ESP) is Authentication Header (AH). Hope this helped!
8 0
2 years ago
Respond to the following in a paragraph of no less than 125 words. Describe the steps to active listening.
Agata [3.3K]

Answer

• Maintaining eye contact

• Paying attention in the talk

• Listening without jumping to conclusion

• Formulating a picture in mind as you listen

• Avoid interruption to suggest solutions

• Asking clarification when the speaker has paused

• Asking questions to improve understanding

• Understanding the mood of the speaker

• Giving the appropriate feedback

Explanation

A person can improve his active listening skills by being aware of his or her personal style of communicating. A good listener is productive  and able to influence others when talking because he or she will have mastered the technique of persuading and negotiating with audience when talking. The journey to becoming an active listener is through paying attention, showing that you are following the speaker ,providing good feedback, avoiding judging the speaker and providing the appropriate feedback.



8 0
2 years ago
Read 2 more answers
01000001 01101110 01110011 01110111 01100101 01110010 00100000 01101001 01110011 00100000 00110100 00110010 00101110 There's a w
BARSIC [14]

Answer:

Binary Code

Explanation:

I believe this is Binary code, so if you enter this in Google, click a translator from binary code to text, and it should tell you.

when I did it, it said "Answer is 42"

Hopefully this helped any.

4 0
2 years ago
Consider an array inarr containing atleast two non-zero unique positive integers. Identify and print, outnum, the number of uniq
Delvig [45]

Answer:

Program.java  

import java.util.Scanner;  

public class Program {  

   public static boolean isPalindrome(String str){

       int start = 0, end = str.length()-1;

       while (start < end){

           if(str.charAt(start) != str.charAt(end)){

               return false;

           }

           start++;

           end--;

       }

       return true;

   }  

   public static int countPalindromePairs(String[] inarr){

       int count = 0;

       for(int i=0; i<inarr.length; i++){

           for(int j=i+1; j<inarr.length; j++){

               StringBuilder sb = new StringBuilder();

               sb.append(inarr[i]).append(inarr[j]);

               if(isPalindrome(sb.toString())){

                   count++;

               }

           }

       }

       return count == 0 ? -1 : count;

   }

   public static void main(String[] args) {

       Scanner sc = new Scanner(System.in);

       String line = sc.next();

       String[] inarr = line.split(",");

       int count = countPalindromePairs(inarr);

       System.out.println("RESULT: "+count);

   }

}

Explanation:

OUTPUT:

3 0
2 years ago
If there are 8 opcodes and 10 registers, a. What is the minimum number of bits required to represent the OPCODE? b. What is the
Nimfa-mama [501]

Answer:  

For 32 bits Instruction Format:

OPCODE   DR               SR1                   SR2      Unused bits

a) Minimum number of bits required to represent the OPCODE = 3 bits

There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.

Ceil (log2 (8)) = 3

b) Minimum number of bits For Destination Register(DR) = 4 bits

There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value.  4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.  

Ceil (log2 (10)) = 4

c) Maximum number of UNUSED bits in Instruction encoding = 17 bits

Total number of bits used = bits used for registers + bits used for OPCODE  

     = 12 + 3 = 15  

Total  number of bits for instruction format = 32  

Maximum  No. of Unused bits = 32 – 15 = 17 bits  

OPCODE                DR              SR1             SR2              Unused bits

  3 bits              4 bits          4 bits           4 bits                17 bits

7 0
2 years ago
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