A pharmaceutical company is attempting to make a large volume of nitrous oxide (NO). They predict they will be able to make a ma
2 answers:
Answer:
52.55% was the percent yield of their process.
Explanation:
Amount of NO expected by pharmaceutical company = 7200 grams
Amount of NO actually obtained by pharmaceutical company = 3784 grams
To calculate the percentage yield, we use the equation:
Experimental yield of nitrous oxide = 3784 grams
Theoretical yield of nitrous oxide = 7200 grams
52.55% was the percent yield of their process.
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Answer:
1.822 g of magnesium hydroxide would be produced.
Explanation:
Balanced reaction:
Compound Molar mass (g/mol)
NaOH 39.997
95.211
58.3197
So, 2.50 g of NaOH = mol of NaOH = 0.0625 mol of NaOH
4.30 g of =
mol of
= 0.0452 mol of
According to balanced equation-
2 mol of NaOH produce 1 mol of
So, 0.0625 mol of NaOH produce mol of NaOH or 0.03125 mol of NaOH
1 mol of produces 1 mol of
So, 0.0452 mol of produce 0.0452 mol of
As least number of moles of are produced from NaOH therefore NaOH is the limiting reagent.
So, amount of would be produced = 0.03125 mol
= g
= 1.822 g
Answer : The expected coordination number of NaBr is, 6.
Explanation :
Cation-anion radius ratio : It is defined as the ratio of the ionic radius of the cation to the ionic radius of the anion in a cation-anion compound.
This is represented by,
When the radius ratio is greater than 0.155, then the compound will be stable.
Now we have to determine the radius ration for NaBr.
Given:
Radius of cation, = 102 pm
Radius of cation, = 196 pm
As per question, the radius of cation-anion ratio is between 0.414-0.732. So, the coordination number of NaBr will be, 6.
The relation between radius ratio and coordination number are shown below.
Therefore, the expected coordination number of NaBr is, 6.
