Question

It is computed that when a basketball player shoots a free​ throw, the odds in favor of his making it are 2020 to 99. Find the probability that when this basketball player shoots a free​ throw, he misses it. Out of every 100 free throws he​ attempts, on the average how many should he​ make?

Answer 1

Answer:

Step-by-step explanation:

Given that when a basketball player shoots a free​ throw, the odds in favor of his making it are 2020 to 99.

Prob that he shoots a free throw = $\frac{99}{2020+99} =0.04672$

a) Probability that when this basketball player shoots a free​ throw, he misses it=1-0.04672 = 0.95328

b) When no of throws = 100 average of throws he makes is

Since x no of throws he makes has two outcomes and each trial is independent , X is binomial with n =100 and p = 0.04672

Expected value of throws = np = 4.672

Answer 2

Answer:

a. 4.672

b.  0.95328

Step-by-step explanation:

It is computed that when a basketball player shoots a free​ throw, the odds in favor of his making it are 2020 to 99. Find the probability that when this basketball player shoots a free​ throw, he misses it. Out of every 100 free throws he​ attempts, on the average how many should he​ make?

Probability is the likelihood of an event to occur or not. Probability that an event will occur or not is usually less than 1

when the player shoots a free​ throw, the odds on his side is 2020 to 99.

P(A), probability of shooting a throw = 99/(2020+99)

P(A)=0.04672

a) Probability that when he shoots a free throw, he misses it will be

P(B)=(1-P(A))=1-0.04672 = 0.95328

b) if the number of throws are 100 average of throws he makes is

the no of throws, n=100

probability of having a free throw=0.04672

Expected value of throws = np = 4.672