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Vladimir79 [104]
2 years ago
6

An architect designs an archway by resting the two bases of an arch on the floor. the shape of the arch can be modeled by the gr

aph of the function f in the CY plane above. if f is defined by f(x)= -2x^2 +20 x where x is in feet what is the value of the distance d in feet between the two base of an arch? A. 2
B. 10
C. 20
D. 40

Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
6 0

Answer: OPTION B.

Step-by-step explanation:

Given the function:

f(x)= -2x^2 +20x

You can rewrite it with f(x)=y. Then:

y= -2x^2 +20x

Now, in order to solve for "x", you can follow this procedure:

1- Substitute y=0 into the function:

0= -2x^2 +20x

2- Factor the equation:

0= -2x(x-10)

Therefore, you get:

x_1=0\\\\x_2=10

This means that the distance between the two bases (in feet) of the arch is:

d=10\ ft

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Answer:

Sum = -81

Step-by-step explanation:

See the comment for complete question.

Given

c = 36 ----- Constant

No coefficient of x^2

Required:

Determine the sum of all distinct positive integers of the coefficient of x

Reading through the complete question, we can see that the question has 3 terms which are:

x^2 ---- with no coefficient

x ---- with an unknown coefficient

36 ---- constant

So, the equation can be represented as:

x^2 + ax + 36 = 0

Where a is the unknown coefficient

From the question, we understand that the equation has two negative integer solution. This can be represented as:

x = -\alpha and x = -\beta

Using the above roots, the equation can be represented as:

(x + \alpha)(x + \beta) = 0

Open brackets

x^2 + (\alpha + \beta)x + \alpha \beta = 0

To compare the above equation to x^2 + ax + 36 = 0, we have:

a = \alpha + \beta

\alpha \beta = 36

Where: \alpha, \beta and \alpha \ne \beta

The values of \alpha and \beta that satisfy \alpha \beta = 36 are:

\alpha = -1 and \beta = -36

\alpha = -2 and \beta = -18

\alpha = -3 and \beta = -12

\alpha = -4 and \beta = -9

So, the possible values of a are:

a = \alpha + \beta

When \alpha = -1 and \beta = -36

a = -1 - 36 = -37

When \alpha = -2 and \beta = -18

a = -2 - 18 = -20

When \alpha = -3 and \beta = -12

a = -3 - 12 = -15

When \alpha = -4 and \beta = -9

a = -4 - 9 = -13

At this point, we have established that the possible values of a are: -37, -20, -15 and -9.

The required sum is:

Sum = -37 -20 -15 - 9

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Answer:

1. Car B is moving east at 70MPh and is in from of car A

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Use the cardinal point system to evaluate the problem first

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Answer:  a) \dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}

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Since we have given that

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