Answer:
Heat loss=85.9W/m^2
ΔT1(Steel)=0.04C
ΔT2(Brick1)=110.13C
ΔT3(Mwood)=343.6C
ΔT1(Brick2)=154.18C
Explanation:
raise the heat transfer equation from the air inside the wall to the outside air from the wall, because that is where you have the temperature data, to find the heat.
To find the temperatures you use the heat found in the previous step, and you use the conduction and convection equations in each wall layer.
I attached the procedure
Answer:
Check the explanation
Explanation:
Given
1) CU traixial compression test
2) Devatoric stress at failure = бd = 50 kN/
3) Confining pressure at failure = бd = 48 kN/
4) Pore pressure at failure = u = 18 kN/
5) Unconfined compression stress = q = 20 kN/
6) Undrained cohesion = q/2 = 20 kN/
To find:
1) Effective and total stress strength failure envelope
Kindly check the attached image below .
Answer:
1113kN
Explanation:
The ouside diameter OD of the pipe is 61cm and the thickness T is 0.9cm, so the inside diameter ID will be:
Inside Diameter = Outside Diameter - Thickness
Inside Diameter = 61cm - 0.9cm = 60.1cm
Converting this diameter to meters, we have:
This inside diameter is useful to calculate the volume V of water inside the pipe, that is the volume of a cylinder:
The problem gives you the water density d as 1.0kg/L, but we need to convert it to proper units, so:
Now, water density is given by the equation , where m is the water mass and V is the water volume. Solving the equation for water mass and replacing the values we have:
With the water mass we can find the weight of water:
Finally we find the total weight add up the weight of the water and the weight of the pipe,so:
Converting this total weight to kN, we have:
Answer:
X_cp = c/2
Explanation:
We are given;
Chord = c
Angle of attack = α
p u (s) = c 1
p1(s)=c2,
and c2 > c1
First of all, we need to find the resultant normal force on the plate and the total moment about leading edge.
I've attached the solution
