Question

If a reaction produces 1.506 kJ of heat, which is trapped in 30.0 g of water initially at 26.5 C on a clorimetr liake hat in Figure 5.12, what is the resulting temperature of water?

Answer 1

Answer: The final temperature of water is 38.5°C

Explanation:

To calculate the amount of heat released or absorbed, we use the equation:

$q=mc\Delta T$

where,

q = heat absorbed = 1.506 kJ = 1506 J   (Conversion factor: 1 kJ = 1000 J)

m = mass of water = 30 g

c = specific heat capacity of water = 4.184 Jl/g.°C

$\Delta T$ = change in temperature = $T_2-T_1=T_2-26.5^oC$

Putting values in above equation, we get:

$1506J=30g\times 4.184J/g.^oC\times (T_2-26.5^oC)\\\\T_2=38.5^oC$

Hence, the final temperature of water is 38.5°C