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iren2701 [21]
2 years ago
13

According to the number line, what is the distance between points A and B? A number line going from negative 16 to positive 12.

A closed circle appears at negative 2 and is labeled A. A closed circle appears at positive 12 and is labeled B. An orange arrow line extends the length of the number line and contains points A and B. 6 units 7 units 12 units 14 units

Mathematics
2 answers:
Anuta_ua [19.1K]2 years ago
7 0

Answer:

6 units

Step-by-step explanation:

On edguenity

DedPeter [7]2 years ago
4 0

Answer: what is the distance between points A and B? 14 Units

Step-by-step explanation: The first thing that you need to do is to draw the number line shown, then we mark the two points mentioned: -2 and 12 and encircle them, following this we are going to count to the right, starting on point A, -2, and finishing on point B, 12. After we count, we are going to see that the distance between the two points is 14 units.

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PLEASE HELP!! Which steps can be used to solve 6/7x+1/2=7/8 for x? Check all that apply. A. Divide both sides of the equation by
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If the probability that a person will die in the next year is 593/100000
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6.8 Use the Normal approximation. Suppose we toss a fair coin 100 times. Use the Normal approximation to find the probability th
Maru [420]

Answer:

(a) The probability that proportion of heads is between 0.30 and 0.70 is 1.

(b) The probability that proportion of heads is between 0.40 and 0.65 is 0.9759.

Step-by-step explanation:

Let <em>X</em> = number of heads.

The probability that a head occurs in a toss of a coin is, <em>p</em> = 0.50.

The coin was tossed <em>n</em> = 100 times.

A random toss's result is independent of the other tosses.

The random variable <em>X</em> follows a Binomial distribution with parameters n = 100 and <em>p</em> = 0.50.

But the sample selected is too large and the probability of success is 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of \hat p<em> </em>(sample proportion of <em>X</em>) if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=100\times 0.50=50>10\\n(1-p)=100\times (1-0.50)=50>10

Thus, a Normal approximation to binomial can be applied.

So,  \hat p\sim N(p,\ \frac{p(1-p)}{n})

\mu_{p}=p=0.50\\\sigma_{p}=\sqrt{\frac{p(1-p)}{n}}=0.05

(a)

Compute the probability that proportion of heads is between 0.30 and 0.70 as follows:

P(0.30

                              =P(-4

Thus, the probability that proportion of heads is between 0.30 and 0.70 is 1.

(b)

Compute the probability that proportion of heads is between 0.40 and 0.65 as follows:

P(0.40

                              =P(-2

Thus, the probability that proportion of heads is between 0.40 and 0.65 is 0.9759.

6 0
2 years ago
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