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1 year ago

The term eof represents

Computers and Technology

2 answers:

rewona [7]1 year ago

8 0

Answer:

EOF stands for End Of File

Google explains it well: EOF is a condition in a computer operating system where no more data can be read from a data source. The data source is usually called a file or stream.

Tamiku [17]1 year ago

5 0

Answer:

EOF( End-Of-File)

Explanation:

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Which of the following are true statements about digital certificates in Web browsers?I. Digital certificates are used to verify

vladimir2022 [97]

Answer:

I only

Explanation:

Digital certificate are virtual encrypted keys or password used by individuals or organization as a means of establishing secure connections between servers and websites so as to be able to authenticate that only the legitimate people are having access to the information.

6 0

1 year ago

A computer has 4 GB of RAM of which the operating system occupies 512 MB. The processes are all 256 MB (for simplicity) and have

Afina-wow [57]

Answer:

$1-p^{14} = 0.99$

$p^{14}= 0.01$

$p =(0.01)^{1/14}= 0.720$

So then the value of the maximum I/O wait that can be tolerated is 0.720 or 72 %

Explanation:

Previous concepts

Input/output operations per second (IOPS, pronounced eye-ops) "is an input/output performance measurement used to characterize computer storage devices like hard disk drives (HDD)"

Solution to the problem

For this case since we have 4GB, but 512 MB are destinated to the operating system, we can begin finding the available RAM like this:

Available = 4096 MB - 512 MB = 3584 MB

Now we can find the maximum simultaneous process than can use with this:

$\frac{3584 MB}{256 MB/proc}= 14 processes$

And then we can find the maximum wait I/O that can be tolerated with the following formula:

$1- p^{14}= rate$

The expeonent for p = 14 since we got 14 simultaneous processes, and the rate for this case would be 99% or 0.99, if we solve for p we got:

$1-p^{14} = 0.99$

$p^{14}= 0.01$

$p =(0.01)^{1/14}= 0.720$

So then the value of the maximum I/O wait that can be tolerated is 0.720 or 72 %

3 0

1 year ago

Brake lights on freeways invite A: law enforcement B: panic C: sudden lane changing D: both B and C E: positive driving habits

Nuetrik [128]

I'am sorry i'am speak spanish

8 0

1 year ago

Suppose that you need to maintain a collection of data whose contents are fixed- i.e., you need to search for and retrieve exist

Keith_Richards [23]

Answer:

Option a: a sorted array

Explanation:

Since the expectation on the data structure never need to add or delete items, a sorted array is the most desirable option. An array is known for its difficulty to modify the size (either by adding item or removing item). However, this disadvantage would no longer be a concern for this task. This is also the reason, linked list, binary search tree and queue is not a better option here although they offer much greater efficiency to add and remove item from collection.

On another hand, any existing items from the sorted array can be easily retrieved using address indexing and therefore the data query process can be very fast and efficient.

4 0

2 years ago

Create a class named BaseballGame that contains data fields for two team names and scores for each team in each of nine innings.

m_a_m_a [10]

Answer:

Check the explanation

Explanation:

BaseballGame:

public class BaseballGame {

protected String[] names = new String[2];

protected int[][] scores;

protected int innings;

public BaseballGame() {

innings = 9;

scores = new int[2][9];

for(int i = 0; i < 9; i++)

scores[1][i] = scores[0][i] = -1;

}

public String getName(int team) {

return names[team];

}

public void setNames(int team, String name) {

names[team] = name;

}

public int getScore(int team, int inning) throws Exception {

if(team < 0 || team >= 2)

throw new Exception("Team is ut of bounds.");

if(inning < 0 || inning >= innings)

throw new Exception("Inning is ut of bounds.");

return scores[team][inning];

}

public void setScores(int team, int inning, int score) throws Exception {

if(team < 0 || team >= 2)

throw new Exception("Team is ut of bounds.");

if(inning < 0 || inning >= innings)

throw new Exception("Inning is ut of bounds.");

if(score < 0)

throw new Exception("Score is ut of bounds.");

for(int i = 0; i < inning; i++)

if(scores[team][i] == -1)

throw new Exception("Previous scores are not set.");

scores[team][inning] = score;

}

HighSchoolBaseballGame:

public class HighSchoolBaseballGame extends BaseballGame {

public HighSchoolBaseballGame() {

innings = 7;

scores = new int[2][7];

for(int i = 0; i < 7; i++)

scores[1][i] = scores[0][i] = -1;

}

LittleLeagueBaseballGame:

public class LittleLeagueBaseballGame extends BaseballGame {

public LittleLeagueBaseballGame() {

innings = 6;

scores = new int[2][6];

for(int i = 0; i < 6; i++)

scores[1][i] = scores[0][i] = -1;

}

6 0

2 years ago