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Vesnalui [34]
2 years ago
15

| 15. Aliyah runs approximately 5.4 miles per hour.

Mathematics
1 answer:
miss Akunina [59]2 years ago
6 0

Answer: 33.33 minutes longer.

Step-by-step explanation :

We need to remember the following formula:

 t=\frac{d}{V}

Where "t" is the time, "d" is the distance and "V" is the speed.

We know that she runs approximately 5.4 miles per hour, then:

V=5.4\ \frac{mi}{h}

Since she plans to run 9 miles on Tuesday, her run's time on Tuesday will be:

t_1=\frac{9\ mi}{5.4\ \frac{mi}{h}}\\\\t_1=\frac{5}{3}\ h

Making the conversion from hours to minutes, we get:

(\frac{5}{3}\ h)(\frac{60\ min}{1\ h})=100\ min

Since she plans to run 12 miles on Thursday, her run's time on that day will be:

t_2=\frac{12\ mi}{5.4\ \frac{mi}{h}}\\\\t_2=\frac{20}{9}\ h

Making the conversion from hours to minutes, we get:

(\frac{20}{9}\ h)(\frac{60\ min}{1\ h})=133.33\ min

Finally in order to find how many longer will her run be on Thursday compared to Tuesday, we need to make the following subtraction:

t_2-t_1=133.33\ min-100\ min=33.33\ min

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Serggg [28]
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-18n = 8m + 4
 /-18    /-18  /-18
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I'm not sure so yeah
7 0
2 years ago
Read 2 more answers
Please answer all of them need this
VikaD [51]

First Question

For a better understanding of the solution provided here please find the first attached file which has the diagram of the the isosceles trapezoid.

We dropped perpendiculars from C and D to intersect AB at Q and P respectively.

As can be seen in \Delta BCQ, we can easily find the values of CQ and BQ.

Since, Sin(75^0)=\frac{CQ}{8}

\therefore CQ=8\times Sin(75^0)\approx 7.73 ft

In a similar manner we can find BQ as:

Cos(75^0)=\frac{BQ}{8}

BQ\approx2.07 ft

All these values can be found in the diagram attached.

Thus, because of the inherent symmetry of the isosceles trapezoid, PQ can be found as:

PQ=22-(AP+QB)=22-(2.07+2.07)=17.86

Let us now consider\Delta AQC

We can apply the Pythagorean Theorem here to find the length of the diagonal AC which is the hypotenuse of \Delta AQC.

AC=\sqrt{(AQ)^2+(QC)^2}=\sqrt{(AP+PQ)^2+(QC)^2}=\sqrt{(2.07+17.86)^2+(7.73)^2}\approx21.38 feet.

Thus, out of the given options, Option B is the closest and hence is the answer.

Second Question

For this question we can directly apply the formula for the area of a triangle using sines which is as:

Area=\frac{1}{2}(First Side)(Second Side)(Sine of the angle between the two sides)

Thus, from the given data,

Area=\frac{1}{2}\times 218.5\times 224.5\times sin(58.2^0)\approx20845 m^2

Therefore, Option D is the correct option.

Third Question

For this question we will apply the Sine Rule to the \Delta ABC given to us.

Thus, from the triangle we will have:

\frac{AB}{Sin(\angle C)}=\frac{BC}{Sin(\angle A)}

\frac{c}{Sin(\angle C)}=\frac{a}{Sin(\angle A)}

\frac{17}{Sin(25^0)}=\frac{a}{Sin(45^0)}

This gives a to be:

a\approx28.44

Which is not close to any of the given options.

Fourth Question

Please find the second attachment for a better understanding of the solution provided her.

As can be clearly seen from the attached diagram, we can apply the Cosine Rule here to find the return distance of the plane which is CA.

AC=\sqrt{(AB)^2+(BC)^2-2(AB)(BC)\times Cos(\angle B)}

\therefore AC=\sqrt{(172.20)^2+(111.64)^2-2(172.20)(111.64)\times Cos(177.29^0)}\approx283.8 miles.

Thus, Option D is the answer.





8 0
2 years ago
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A giraffe measures 17 feet tall . A gorilla mesures 63 inches tall. How many feet taller is the giraffe than the gorilla
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Answer:

11.75 feet

Step-by-step explanation:

17 times 12 = 204 inches

204 - 63 = 141 inches

141/12 = 11.75 feet

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Answer:

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4. Standard deviation is useful because it has the same units as the underlying data.

Step-by-step explanation:

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Answer:

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