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arlik [135]
2 years ago
12

Your younger brother likes to rub his feet on the carpet and then touch you to give you a shock. While you are trying to escape

the shock treatment, you discover a hollow metal cylinder in your basement, large enough to climb inside. In which of the following cases will you not be shocked? You climb inside the cylinder, making contact with the inner surface, and your charged brother touches the outer metal surface. Both of you are outside the cylinder, touching its outer metal surface but not touching each other directly. Your charged brother is inside touching the inner metal surface and you are outside, touching the outer metal surface.
Engineering
1 answer:
Setler79 [48]2 years ago
3 0

Answer:

A.  You climb inside the cylinder, making contact with the inner surface, and your charged brother touches the outer metal surface.

Explanation:

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Add a calculated field named AccountTime that calculates the number of days each client's accounts have been open. Assume today'
Troyanec [42]

Answer:

The following steps should be followed to create the calculated field:

1. Enter AccountTime: (The AccountTime must be enclosed in #). #12/31/2017#-OpenDate in the first empty field.

2. Right-click the field then click properties. This will allow you format the selected field.

3. Rght-click the query tab and click Save. This will allow you save the query

4. Lastly, Close the query.

5 0
2 years ago
Define a) Principal Plane b) Principal Stress c) anelasticity d) yield point e) ultimate tensile stress f) hardness g) toughness
bagirrra123 [75]

Answer:

Principal Plane: It is that plane in a stressed body over which no shearing stresses act. As we know that in a stressed body on different planes 2 different kind of stresses act normal stresses acting normal to the plane ans shearing stresses acting in the plane. The special planes over which no shearing stresses act and only normal stresses are present are termed as principal planes.

Principal Stress: The stresses in the principal planes are termed as normal stresses.

Anelasticity: It is the behavior of a material in which no definite relation can found to exist between stress and strain at any point in the stressed body.

Yield Point: It is the point in the stress-strain curve of a body at which the stress in the body reaches it's yield value or the object is just about to undergo plastic deformation if we just increase value of stress above this value. It is often not well defined in high strength materials or in some materials such as mild steel 2 yield points are observed.

Ultimate tensile strength: It is the maximum value of stress that a body can develop prior to fracture.

Hardness: it is defined as the ability of the body to resist scratches or indentation or abrasion.

Toughness: It is the ability of the body to absorb energy and deform without fracture when it is loaded. The area under the stress strain curve is taken as a measure of toughness of the body.

Elastic limit: The stress limit upto  which the body regains it's original shape upon removal of the stresses is termed as elastic limit of the body.

4 0
2 years ago
An annealed copper strip of 228 mm wide and 25 mm thick being rolled to a thickness of 20 mm, in one pass. The roll radius is 30
sdas [7]

Answer:

The roll force is 1.59 MN

The power required in this operation is 644.96 kW

Explanation:

Given;

width of the annealed copper, w = 228 m

thickness of the copper, h₀ = 25 mm

final thickness, hf = 20 mm

roll radius, R = 300 mm

The roll force is given by;

F = LwY_{avg}

where;

w is the width of the annealed copper

Y_{avg} is average true stress of the strip in the roll gap

L is length of arc in contact, and for frictionless situation it is given as;

L = \sqrt{R(h_o-h_f)} \\\\L = \sqrt{300(25-20)}\\\\L = 38.73 \ mm

Now, determine the average true stress, Y_{avg}, for the annealed copper;

The absolute value of the true strain, ε = ln(25/20)

ε = 0.223

from true stress vs true strain graph; at true strain of 0.223, the true stress is 280 MPa.

Then, the average true stress = ¹/₂(280 MPa.) = 180 MPa

Finally determine the roll force;

F = LwY_{avg}

F = (\frac{38.73 }{1000})(\frac{228}{1000})*180 \ MPa\\\\F =   1.59 \ MN

The power required in this operation is given by;

P = \frac{2\pi FLN}{60}\\\\P =  \frac{2\pi (1.59*10^6)(0.03873)(100)}{60}\\\\P = 644955.2 \ W\\\\P = 644.96 \ kW

5 0
2 years ago
What properties should the head of a carpenter’s hammer possess? How would you manufacture a hammer head?
BabaBlast [244]

Properties of Carpenter's hammer possess

Explanation:

1.The head of a carpenter's hammer should possess the impact resistance, so that the chips do not peel off the striking face while working.

2.The hammer head should also be very hard, so that it does not deform while driving or eradicate any nails in wood.

3.Carpenter's hammer is used to impact smaller areas of an object.It can drive nails in the wood,can crush  the rock and shape the metal.It is not suitable for heavy work.

How hammer head is manufactured :

1.Hammer head is produced by metal forging process.

2.In this process metal is heated and this molten metal is placed in the cavities said to be dies.

3.One die is fixed and another die is movable.Ram forces the two dies under the forces which gives the metal desired shape.

4.The third process is repeated for several times.

5 0
2 years ago
. A cylindrical metal specimen having an original diameter of 12.8 mm (0.505 in.) and gauge length of 50.80 mm (2.000 in.) is pu
kogti [31]

Answer:

% reduction in area==PR=0.734=73.4%

% elongation=EL=0.42=42%

Explanation:

given do=12.8 mm

df=6.60

Lf=72.4 mm

Lo=50.8 mm

% reduction in area=((\pi*(do/2)^2)-(\pi*(df/2)^2)))/\pi*(do/2)^2

substitute values

% reduction in area=73.4%

% elongation=EL=((Lf-Lo)/Lo))*100

% elongation=((72.4-50. 8)/50.8)*100=42%

6 0
2 years ago
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