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skelet666 [1.2K]
2 years ago
11

A 150-in.3, four-cylinder, four-stroke cycle, high-swirl CI engine is running at 3600 RPM. Bore and stroke are related by S = 0.

95 B. During the compression stroke, the cylinder air has a swirl ratio, as defined by Eq. (6-2), of 8. Calculate: (a) Swirl tangential speed. [ft/sec] (b) Angular velocity of cylinder air using the paddle wheel model. [rev/see]

Engineering
1 answer:
Free_Kalibri [48]2 years ago
6 0

Answer:

Explanation:

(a) Swirl tangential speed = 3 x MPS ( mean piston speed)

= 3 x 420.76 inch/sec = 280.51  [ft/sec]

The other detailed steps is as shown in the attached file

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Consider water at 27°C in parallel flow over an isothermal, 1‐m‐long flat plate with a velocity of 2 m/s. a) Plot the variation
yulyashka [42]

Answer:

i) h-bar-L = 4110 W/m^2K

ii ) h-bar-L = 4490 W/m^2K

iii) h-bar-L = 5072 W/m^2K

Explanation:

Given:-

- The temperature of water, T = 27°C

- The velocity of fluid flow, U∞ = 2m/s

- The length of the flat place, L = 1 m

Solution:-

- Using table A-6, to determine the properties of water:

                   Density ρ = 997 kg/m^3

                   Dynamic viscosity ν = 0.858*10^-6 m^2/s

                   Pr = 583 , k = 0.613 W/m.K

- The reynold's number for full length (L = 1m):

                   Re = U∞*L / ν

                   Re = (2)*(1) / (0.858*10^-6)

                  Re = 2.33*10^6

- The boundary layer is mixed with Rex,c = 5*10^5. Evaluate the critical length (xc):

                 xc = L* ( Rex,c / Re )

                      = (5*10^5 / 2.33*10^6 )

                      = 0.215 m

a) Using "IHT correlation tool, External Flow, Local coefficients for laminar or Turbulent flows", h (x) was evaluated and plotted with critical Reynolds number for all 3 cases: (i) 5 × 10^5, (ii) 3 × 10^5, and (iii) 0 (the flow is fully turbulent). - (See attachment 1)

b) Using "IHT correlation tool, External Flow, Average coefficients for laminar or Mixed flows", h - bar- (x) was evaluated and plotted with critical Reynolds number for all 3 cases: (i) 5 × 10^5, (ii) 3 × 10^5, and (iii) 0 (the flow is fully turbulent). - (See attachment 2)

c) The average convection coefficient for the plate can be determined from the graphs presented in (Attachments 1 and 2). Since,

                                    h-bar-L = h-bar-x(L)

The values for the flow conditions are:

             ( i) h-bar-L = 4110,  ii ) h-bar-L = 4490 , iii) h-bar-L = 5072 ) W/m^2K

                   

6 0
2 years ago
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