Decompose the signal (1+ 0.1 cos5t) cos100t into a linear combination of sinusoidal functions, and find the amplitude, frequency
, and phase of each component. Hint: use the identity for cos a cos b.
1 answer:
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Answer:
number of pulses produced = 162 pulses
Explanation:
give data
radius = 50 mm
encoder produces = 256 pulses per revolution
linear displacement = 200 mm
solution
first we consider here roll shaft encoder on the flat surface without any slipping
we get here now circumference that is
circumference = 2 π r .........1
circumference = 2 × π × 50
circumference = 314.16 mm
so now we get number of pulses produced
number of pulses produced = × No of pulses per revolution .................2
number of pulses produced = × 256
number of pulses produced = 162 pulses
Answer:
ΔKE=-347.278 kJ
ΔPE= 441.45 kJ
Explanation:
given:
mass m=900 kg
the gravitational acceleration g=9.81 m/s^2
the initial velocity =100 km/h-->100*10^3/3600=27.78 m/s
height above the highway h=50 m
h1=0m
the final velocity =0 m/s
<u>To find:</u>
the change in kinetic energy ΔKE
the change in potential energy ΔPE
<u>assumption:</u>
We take the highway as a datum
<u>solution:</u>
ΔKE=5*m*(^2-
^2)
=-347.278 kJ
ΔPE=m*g*(h-h1)
= 441.45 kJ