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JulsSmile [24]
2 years ago
7

SSHA scores Here are the scores on the Survey of Study Habits and Attitudes (SSHA) for 18 first-year college women:154 109 137 1

15 152 140 154 178 101 103 126 126 137 165 165 129 200 148and for 20 first-year college men:108 140 114 91 180 115 126 92 169 146 109 132 75 88113 151 70 115 187 104Do these data support the belief that women have better study habits and attitudes toward learning than men? (Note that high scores indicate good study hab its and attitudes toward learning.) Follow the four-step process.
Mathematics
1 answer:
mihalych1998 [28]2 years ago
5 0

Answer:

Women has better study habit than men.

Step-by-step explanation:

For knowing who has better study habits and attitudes toward learning we have to find the mean of both the women and men data.

The first step is that we only take first 18 values of both women(X) and men(Y) data, to make them of same length

Mean is used to measure the central tendency of data which represents the whole data in the best way. It can be found as the ratio of the sum of all the observations to the total number of observations.  

Calculating all values:

\bar{X} = 141.0556

\bar{Y} = 121.25

Thus, women has better study habit than men. Since Mean of X is larger than Mean of Y.

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Jessie runs four days a week after school She
Usimov [2.4K]

Answer:

she runs 8 miles on Monday 8 miles on Wednesday 8 miles on Thursday and 5 miles on Friday

Step-by-step explanation:

8+8+8+5 = 29

3 0
2 years ago
A new car is purchased for 22400 dollars. The value of the car depreciates at 11% per year. To the nearest tenth of a year , how
m_a_m_a [10]

Answer:

t= 12.9 years

Step-by-step explanation:

Value after t years = initial value ( 1 - r )^t

Where,

Value after t years= $5000

Initial value = $22,400

r= depreciation rate = 11%

t= length of time (years)

Value after t years = initial value ( 1 - r )^t

5000 = 22,400 ( 1 - 0.11)^t

5000 = 22,400(0.89)^t

Divide both sides by 22,400

(0.89)^t = 5000 / 22,400

(0.89)^t = 0.2232

Take the log of both sides

t log 0.89 = log 0.2232

t= log 0.2232 / log 0.89

= -0.6513 / -0.0506

= 12.87

t= 12.9 years

5 0
2 years ago
A water trough has two congruent isosceles trapezoids as ends and two congruent rectangles as sides.
BlackZzzverrR [31]

Answer:

Part a) The exterior surface area is equal to 160\ ft^{2}

Part b) The volume is equal to 240\ ft^{3}

Part c) The volume water left in the trough will be 84\ ft^{3}

Step-by-step explanation:

Part a) we know that

The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles

so

<em>Find the area of two rectangles</em>

A=2[12*5]=120\ ft^{2}

<em>Find the area of two trapezoids</em>

A=2[\frac{1}{2}(8+2)h]

Applying Pythagoras theorem calculate the height h

h^{2}=5^{2}-3^{2}

h^{2}=16

h=4\ ft

substitute the value of h to find the area

A=2[\frac{1}{2}(8+2)(4)]=40\ ft^{2}

The exterior surface area is equal to

120\ ft^{2}+40\ ft^{2}=160\ ft^{2}

Part b) Find the volume

We know that

The volume is equal to

V=BL

where

B is the area of the trapezoidal face

L is the length of the trough

we have

B=20\ ft^{2}

L=12\ ft

substitute

V=20(12)=240\ ft^{3}

Part c)

<em>step 1</em>

Calculate the area of the trapezoid for h=2 ft (the half)

the length of the midsegment of the trapezoid is (8+2)/2=5 ft

A=\frac{1}{2}(5+2)(2)=7\ ft^{2}

<em>step 2</em>

Find the volume

The volume is equal to

V=BL

where

B is the area of the trapezoidal face

L is the length of the trough

we have

B=7\ ft^{2}

L=12\ ft

substitute

V=7(12)=84\ ft^{3}

4 0
2 years ago
What are the zeros of the quadratic function f(x) = 6x2 + 12x – 7?
zalisa [80]

we have

f(x) = 6x^{2} + 12x -7

To find the zeros equate the function to zero

6x^{2} + 12x -7=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

7= 6x^{2} + 12x

Factor the leading coefficient

7= 6(x^{2} + 2x)

Complete the square. Remember to balance the equation by adding the same constants to each side

7+6= 6(x^{2} + 2x+1)

13= 6(x^{2} + 2x+1)

Rewrite as perfect squares

13= 6(x+1)^{2}

(13/6)=(x+1)^{2}

square root both sides

x+1=(+/-)\sqrt{\frac{13}{6}}

x=-1(+/-)\sqrt{\frac{13}{6}}

x1=-1+\sqrt{\frac{13}{6}}

x2=-1-\sqrt{\frac{13}{6}}

therefore

the answer is

The zeros of the quadratic function are

x=-1+\sqrt{\frac{13}{6}} and x=-1-\sqrt{\frac{13}{6}}


3 0
2 years ago
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