Whats 4.029 in expanded form and with number names

A company produces remote-controlled helicopters. The company’s profit, in thousands of dollars, as a function of the number of

muminat

Answer:

When 6 helicopters are produced weekly, the company's profit is <u>14 thousand dollars.</u>

Step-by-step explanation:

As per the given statement:

The company profit (in thousands of dollars), as a function of the number of helicopters produced per week can be modeled by a function.

The function that models the scenario is:

$f(h) = -2(h-4)^2 +22$ ......[1]

where

f(h) represents the company's profit

h represents the number of helicopters produced per week.

It is also given that when 1 helicopter is produced per week, the company’s profit is 4 thousand dollars.

Maximum profit for company 22 thousand dollars, occurs when 4 helicopters are produced per week

⇒ $f(1) = 4$ and $f(4) = 22$

we have to find when 6 helicopters are produced weekly, the company profit is;

⇒ h = 6 helicopters

Substitute this value in [1] to solve for f(6);

$f(6) = -2(6-4)^2 +22$

= $-2(2)^2 +22 = -2 \times 4 + 22 = -8 + 22 = 14$

Therefore, the company profit is, 14 thousand dollars.

4 0

2 years ago

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Determine whether the series is convergent or divergent. 1 2 3 4 1 8 3 16 1 32 3 64 convergent divergent Correct:

Vanyuwa [196]

Answer:

This series diverges.

Step-by-step explanation:

In order for the series to converge, i.e. $\lim_{n \to \infty} a_n =A$ it must hold that for any small $\epsilon$ >0, there must exist $n_0\in \mathbb{N}$ so that starting from that term of the series all of the following terms satisfy that $|a_n-A|n_0$ .

It is obvious that this cannot hold in our case because we have three sub-series of this observed series. One of them is a constant series with $a_n=1$ , the other is constant with $a_n=3$ , and the third one has terms that are approaching infinity.

Really, we can write this series like this:

$a_n=\begin{cases} 1 \ , \ n=4k+1, k\in \mathbb{N}_0\\ 2^{k}\ , \ n=2k, k\in \mathbb{N}_0\\3\ , \ n=4k+3, k\in \mathbb{N}_0\end{cases}$

If we denote the first series as $b_n=1$ , we will have that $\lim_{k \to \infty} b_k=1$ .

The second series is denoted as $c_k=2^k$ and we have that $\lim_{k \to \infty} c_k=+\infty$ .

The third sub-series $d_k=3$ is a constant series and it holds that $\lim_{k \to \infty} d_k=3$ .

Since those limits of sub-series are different, we can never find such $n_0\\$ so that every next term of the entire series is close to one number.

To make an example, if we observe the first sub-series if follows that A must be equal to 1. But if we chose $\epsilon =1$ , all those terms associated with the third sub-series will be out of this interval $(A-1, A+1)=(0, 2)$ .

Therefore, the observed series diverges.

5 0

2 years ago

A book has 89 pages, but the page numbers are printed incorrectly. Every third page number has been omitted, so that the pages a

Sphinxa [80]

Answer:

89

Step-by-step explanation:

There are only 30 pages but last page number is 89.

8 0

2 years ago

The distance between place A and place B is 60 miles. the distance from place A to place C is 15% of the distance from place A t

iren [92.7K]

$\frac{15}{100} = \frac{d}{60} \\ 100d = 900 \\ d = 9$

8 0

2 years ago

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The image shows a ray of light bending at the boundary of a glass block. According to a law of optics, = n, where n is a constan

UkoKoshka [18]

The formula for the light bend would be n1*sin i= n2 * sin r

If you use "sin (90-x)= cos x" principle, you can change the sin in the equation into
n1*sin i= n2 * sin r
n1 * cos a= n2 * cos b
n2/n1= cos a/ cos b

Assuming the n constant is the ratio of the glass compared to water then the answer would be: cos a/ cos b

3 0

2 years ago