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alexira [117]
2 years ago
4

Figure abcd is a kite. Find the value of x. ​

Mathematics
1 answer:
Sphinxa [80]2 years ago
5 0

Answer:

x = 30

Step-by-step explanation:

(x+20) + (x+10) +90 = 180

(2x+30) + 90 = 180

2x+120 = 180

2x = 60

x = 30

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F(x, y) = x2 + y2 + 4x − 4y, x2 + y2 ≤ 81 find the extreme values of f on the region described by the inequality.
Whitepunk [10]
Take partial derivatives and set them equal to 0:

\nabla F(x,y)=\langle2x+4,2y-4\rangle=\mathbf 0

We find one critical point within the boundary of the disk at (x,y)=(-2,2). The Hessian matrix for this function is

\mathbf H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}2&0\\0&2\end{bmatrix}

which is positive definite, and incidentally independent of x and y, so F(x,y) attains a minimum F(-2,2)=-8.

Meanwhile, we can parameterize the boundary by \mathbf r(t)=\langle9\cos t,9\sin t\rangle with 0\le t\le2\pi, which gives

F(x,y)=F(x(t),y(t))=f(t)=81\cos^2t+81\sin^2t+36\cos t-36\sin t=81+36(\cos t-\sin t)

with critical points at

f'(t)=0\implies 36(-\sin t-\cos t)=0\implies\sin t+\cos t=0\implies t=\dfrac{3\pi}4,\dfrac{7\pi}4

At these points, we get

f\left(\dfrac{3\pi}4\right)=81-36\sqrt2\approx30.0883
f\left(\dfrac{7\pi}4\right)=81+36\sqrt2\approx131.9117

so we attain a maximum only when t=\dfrac{7\pi}4, which translates to (x,y)=\left(\dfrac9{\sqrt2},-\dfrac9{\sqrt2}\right).
3 0
2 years ago
The truth table represents statements p, q, and r. p q r p ∧ q p ∧ r A T T T T T B T T F T F C T F T F T D T F F F F E F T T F F
maksim [4K]

The table shows the results of (p ^ q) and results of  (p ^ r) for all possible outcomes. We have to tell which of the outcomes of union of both these events will always be true.

(p ^ q) V (p ^ r) means Union of (p ^ q) and (p ^ r). The property of Union of two sets/events is that it will be true if either one of the event or both the events are true i.e. there must be atleast one True(T) to make the Union of two sets to be True. 

So, (p ^ q) V (p ^ r)  will be TRUE, if either one of  (p ^ q) and (p ^ r)  or both are true. From the given table we can see that only the outcomes A, B and C will result is TRUE. The rest of the outcomes will all result in FALSE.

Therefore, the answer to this question is option 2nd

5 0
2 years ago
An exterior angle of an isosceles triangle has measure 130°. Find two possible sets of measures for the angles of the triangle.
frozen [14]
(1) it can be both exterior of vertex or base. 180-130=50°
vertex is 50°:     base=(180-50)/2=65°
base is 50°:       vertex= 180-2*50=80°

vertex 50 base 65; vertex 80, base 50

(2)base=180-130=50°
vertex=180-2*50=80°

base 50 vertex 80
5 0
2 years ago
Please help I will give brainliest
lutik1710 [3]

Answer:

Angle PQW is equal to 35 degrees

Step-by-step explanation:

Angle PQW = 36x - 1

Angle WQR = 134x

Angle PQR = 169 degrees

To find angle PQW, Set Angles PQR and WQR to PQW. The equation should look like this:

PQR - WQR = PQW

Substitute in the values

169 - 134x = 36x - 1

Now add 134x to both sides and add 1 to both sides.

170 = 170x

Now divide 170 from both sides

x = 1

Plug x into angle PQW

36(1) - 1 = 35

6 0
2 years ago
Willis bought a gallon of paint. He painted a wall that is 9 ft high and 10 ft wide. Then he used the rest of the paint to paint
GalinKa [24]
Well 9×10 is 90, 90+46 is 136. the paint covered 136 square feet
4 0
2 years ago
Read 2 more answers
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