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2 years ago

Explain two ways you could solve 20 = 5(-3 + x)

Mathematics

1 answer:

MrRissso [65]2 years ago

3 0

Answer:

The answer to your question is below

Step-by-step explanation:

First way

20 = 5(-3 + x) expand

20 = -15 + 5x simplify like terms

5x = 20 + 15

5x = 35 divide both sides by 5

5x/5 = 35/5

x = 7

Second way

20/5 = 5/5 (-3 + x) Divide both sides by 5

4 = -3 + x Add +3 in both sides

4 + 3 = -3 + 3 + x Simplify like terms

7 = x

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$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill$

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