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2 years ago

Denise is making bean bags. She has 6.4 pounds of beans.

Mathematics

1 answer:

dezoksy [38]2 years ago

5 0

Answer:

a) she be able to make 8 bags

b) she can make 16 bags.

Step-by-step explanation:

According to the exercise info Denise has 6.4 pounds of beans

<u>Solving question a </u>

⇒ if she makes each bean bag of 0.8 pounds and she has 6.4 pounds of beans, we can express this by using the three simply rule she needs to puts 6.4 pounds of beans in x quantity of bags of 0.8 pouns, so doing the division: 6. 4 pounds of beans / 0.8 pounds of beans per bag= 8 bags of 0.8 pounds of beans.

B- If she decides to make mini bean bags that are half as heave as the ohers bags, so now Denise is going to make bags of 0.8/2 = 0.4 pounds.

Doing the same procedure as question a, we can say that she has 6.4 pounds of beans and she needed to put these amount in a x quantity of 04 pounds bags. Doing the following division ⇒ 6.4 pounds of beans/ 0.4 pounds of beans per bag= 16 bags

In conclusion she is going to make 16 bags of 0.4 pounds of beans.

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zavuch27 [327]

Answer:

$0.5a+7.5b^2$

Step-by-step explanation:

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2 years ago

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sasho [114]

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2 years ago

There are 10 pots exposed in the shop, 2 of which have hidden defects. the customer buys two pieces. what is the probability tha

Tpy6a [65]

Check the tree diagram, of all the possible scenarios and the probabilities.

All the possible scenarios are:

1st.non defective, 2nd.non defective
1st.non defective, 2nd. defective
1st. defective, 2nd. non defective
1st. defective, 2nd. defective

consider the case 1st.non defective, 2nd.non defective

the probability that the first one is non defective is 8/10, since 8 out of 10 are non defective.

In this scenario, the second one is non defective as well. The probability for this to happen is 7/9, since now we have 7 non defective pots, and 9 in total.

This means that the probability of the first to be non defective, and the second non-defective is (8/10) * (7/9)=0.622

similarly we calculate the other cases, as shown in the picture.

P(at least one is defective)=
P(1st.non defective, 2nd. defective)+P(1st. defective, 2nd. non defective)+P(1st. defective, 2nd. defective)=
0.178+0.178+0.022=0.378

Answer: 0.378

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1 year ago

mike and mandy bought the same item mike aid 15,000 mandy got a discount and paid 3,00 less how much of a discount did she get??

Arada [10]

She got a 20% discount (or 80% discount). (Work shown for 80%).
First you have to find out how much Mandy paid. So from 15000 you will subtract 3000. 15000-3000=12000.
Next you need to set up your equation. $\frac{1200}{15000}= \frac{x}{100}$ . You then have to cross multiply. So 100 times 12000, 100*12000=1200000. And 15000 times x is 15000x. Finally you divide both sides by 15000. And 1200000 divided by 15000 is 80. X=80

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1 year ago

Read 2 more answers

A portfolio has average return of 13.2 percent and standard deviation of returns of 18.9 percent. Assuming that the portfolioi's

wlad13 [49]

Answer:

B. 0.835

Step-by-step explanation:

We can use the z-scores and the standard normal distribution to calculate this probability.

We have a normal distribution for the portfolio return, with mean 13.2 and standard deviation 18.9.

We have to calculate the probability that the portfolio's return in any given year is between -43.5 and 32.1.

Then, the z-scores for X=-43.5 and 32.1 are:

$z_1=\dfrac{X_1-\mu}{\sigma}=\dfrac{(-43.5)-13.2}{18.9}=\dfrac{-56.7}{18.9}=-3\\\\\\z_2=\dfrac{X_2-\mu}{\sigma}=\dfrac{32.1-13.2}{18.9}=\dfrac{18.9}{18.9}=1\\\\\\$

Then, the probability that the portfolio's return in any given year is between -43.5 and 32.1 is:

$P(-43.5$

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