40,897 in expanded form
1 answer:
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<h2>Answer:</h2>
The area of the top surface of the washer is: 160.14 square mm.
<h2>Step-by-step explanation:</h2>The top of the surface is in the shape of a annulus with a outer radius of 10 mm and a inner radius of 7 mm ( since the diameter of the hole is: 14 mm and we know that the radius is half of the diameter)
Now, we know that the area of the annulus region is given by:
where R is the outer radius and r is the inner radius.
Here we have:
Hence, we have:
Since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to 
.
---> equation (1)
By using pythagoras rule which states that the
---> equation (2)
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,
substitute this value in equation (1) then
where A is the area of the square whose side is x
By using pythagoras rule which states that the
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,
where A is the area of the square whose side is x