Answer:
212m
Step-by-step explanation:
The set up will be equivalent to a right angled triangle where the height is the opposite side facing the 45° angle directly. The length of the rope will be the slant side which is the hypotenuse.
Using the SOH, CAH, TOA trigonometry identity to solve for the length of the rope;
Since we have the angle theta = 45° and opposite = 150m
According to SOH;
Sin theta = opposite/hypotenuse.
Sin45° = 150/hyp
hyp = 150/sin45°
hyp = 150/(1/√2)
hyp = 150×√2
hyp = 150√2 m
hyp = 212.13m
Hence the length of the rope for the kite sail, in order to pull the ship at an angle of 45° and be at a vertical height of 150 m is approximately 212m
Angle 4 equals 34 degrees since angle 2 and 4 are opposite angles and opposite angles are congruent
The function of the trapezoid area is:
A(x)=(B+b)*h/2
Where B and b are the bases and h is the height.
With the given data: h=10 B and b =7 and x (it may vary which one is bigger)
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So that function becomes:
A(x)=(7+x)*10/2
A(x)=(7+x)*5
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So if you want the inverse function, you have to operate to find x:
A(x)/5=7+x
A(x)/5-7=x
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So the new function is:
x(A)=A/5-7
