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RSB [31]
2 years ago
13

Windsor Hospital purchases $90,000 in surgical equipment on October 1, Year 1. The useful life is estimated to be 5 years, and t

he residual value is estimated to be $10,000. What will be the depreciation expense reported for this equipment in Year 1 if the hospital uses the straight-line method?
Business
1 answer:
AVprozaik [17]2 years ago
5 0

Answer:

The depreciation expense for year 1 is $16,000

Explanation:

Depreciation: The depreciation was occurred due to tear and wear, obsolesce, time period, etc

Under the straight-line method, the depreciation should be charged with the same amount over the useful life.

The calculation is shown below:

= \dfrac{(original\ cost - residual\ value)}{(useful \ life)}

= \dfrac{(\$90,000 - \$10,000)}{(5 \ years)}

= $16,000

The depreciation should be charged for $16,000 in year 1. Moreover, it is shown in the income statement in the debit side and in the cash flow statement also.

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C. Businesses create goods for product markets to sell.

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Explanation:

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Gerald is very good with customers, is friendly, and works well with a team. Which career is Gerald most likely a part of? Nucle
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I think this is the answer.....

Hope this helps lmo

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2 years ago
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The united states department of agriculture (usda) found that the proportion of young adults ages 20–39 who regularly skip eatin
Sunny_sXe [5.5K]

Answer:

probability  = 0.3557

Explanation:

given data

young adults ages =  20 to 39

skip eating breakfast p = 0.238

random sample of size n = 500

to find out

we find the probability that the number of individuals in Lance's sample who regularly skip breakfast is greater than 122

solution

we use here Normal Approximation to Binomial Distribution

so first consider random variable = x

so

x~ Bin (n,p)   .............1

and here Normal Approximation will be

x~ Normal Approx (np, npq)    .................2

so it will be

x~ (500, 0.238)  

as here we know q will be

q = 1 - p

q = 1 - 0.238

q = 0.762    .............3

so

here x~ Normal Approx (119, 90.678)

and now we get P(X > 122)

so

We will convert it to Z by as that

z = \frac{x-\mu}{\sigma}     ................4

and here

mean  \mu = np

and standard deviation \sigma =  \sqrt{npq}

so here for P(X > 122)

P(\frac{X-\mu}{\sigma}>\frac{122-119}{\sqrt{90.678}})     ............5

and it is  P(Z>0.37)

so

probability  = 1 - P(Z<0.37)

now we use here z table for value

probability  = 1-0.6443

probability  = 0.3557

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1 year ago
Large data units are broken into smaller pieces by a process called
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The answer in the description above is segmentation. This is the process of which large data undergone into having their properties to be broken into small pieces in which will help in having them to fit with a specific TCP segment.

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