Section A = 22,500 seats
section B = 14,900 seats
section C = 7,600 seats
Answer:
32
Explanation:
First bounce = 13 / 14 × 10 = 130 /14
using geometric progression where the common ratio = 13/14, the first bound = 130/14
ar^n-1 < 1
substitute the values into the equation
130 /14 × 13/14^(n-1) < 1
(13/14)^n-1 < 1÷ (130/14)
(13/14)^n-1 < 14 / 130
take log of both side
log (13 /14)^n-1 < log ( 14/130)
n-1 log (13 /14) < log ( 14/130)
since log (13/14) negative
n-1 > (log( 14/130)) ÷ ( log (13/14)
n - 1 > 30.07
n > 30.07 + 1 > 31.07
The 32 bounce will the first less than 1 foot
Answer:
270,000 units
Explanation:
Given that:
Beginning Inventory for finished goods: 31,000
Ending Inventory for finished goods : 41,000
Beginning Inventory for raw materials: 61000
Ending Inventory for raw materials: 51,000
Units planned to be sold: 260,000
We compute the produced finished goods = Ending inventory + Units sold − Beginning inventory
= 41,000 + 260,000 − 31,000 = 270,000
The number of units the company would have to manufacture during the year would be 270,000
Answer:
A. Using a cap-and-trade system of tradable emission allowances will eliminate half of the sulfur dioxide pollution at a cost of $5,000 million per year.
B. If permits cannot be traded, then the cost of the pollution reduction will be $6,000 million per year
Explanation:
A. Using a cap-and-trade system of tradable emission allowances will eliminate half of the sulfur dioxide pollution at a cost of $5,000 million per year.
(250x20) =$5000
B. If permits cannot be traded, then the cost of the pollution reduction will be $6,000 million per year
[250(10)+350(10)]
=$2,500+$3,500
=$6,000
