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zvonat [6]
2 years ago
8

A study conducted at a certain college shows that​ 65% of the​ school's graduates find a job in their chosen field within a year

after graduation. Find the probability that 11 randomly selected graduates all find jobs in their chosen field within a year of graduating. Round to the nearest thousandth if necessary. Round to three decimal places as needed.
Mathematics
1 answer:
alexdok [17]2 years ago
8 0

Answer: 0.009

Step-by-step explanation:

Formula we use here : Binomial distribution formula

Probability of getting success sin x trial =P(X)=^nC_xp^x(1-p)^{n-x} , where n is the sample size and p is the probability of success in each trial .

Given : A study conducted at a certain college shows that​ 65% of the​ school's graduates find a job in their chosen field within a year after graduation.

i.e. p= 0.65

Sample size : n= 11

Now, the probability that 11 randomly selected graduates all find jobs in their chosen field within a year of graduating:-

P(X)=^{11}C_{11}(0.65)^{11}(1-0.65)^{11-11}\\\\=(1)(0.65)^{11}(1)\\\\=0.00875078317401\approx0.009

Hence, the probability that 11 randomly selected graduates all find jobs in their chosen field within a year of graduating = 0.009

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B) The method used is Relative frequency approach.

Step-by-step explanation:

From the question, we are told a sample of n kids line up for recess.

Now, the order in which they line up is random with each ordering being equally likely. Thus, this means that the probability of each kid to take a position is n(total of kids/positions).

Since we are being asked about 3 kids from the class, let's assign a letter to each kid:

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In this case, the events are not mutually exclusive, since it's possible that "Betty is first but Mary is not last" or "Mary is last but Betty is not first" or "Betty is the first in line and Mary is last". Thus, there is an intersection between them and the probability is symbolized as;

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The suffix 1 refers to the first position while the suffix n refers to the last position.

Also, P(B₁ ∩ Mₙ) = P(B₁) × P(Mₙ/B₁)

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Also, let n_A be the number of times that A did occur.

Now, the relative frequency would be written as (n_A)/n.

Thus, in this method, we will define P(A) as:

P(A) = lim:n→∞[(n_A)/n]

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