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polet [3.4K]
2 years ago
11

Demand for an electric fan is related to its selling price p (in dollars) by the equation n = 1960 − 70 p where n is the number

of fans that can be sold per month at a price p . Find the selling price that will maximize the revenue.

Mathematics
1 answer:
alexandr402 [8]2 years ago
7 0

Answer:

  $14

Step-by-step explanation:

The revenue from sales of fans is the product of the number of fans sold and the price at which they are sold:

  R(p) = n·p = (1960-70p)p

  R(p) = 70(28 -p)p

This equation describes a parabola that opens downward and has zeros at p=0 and p=28. The axis of symmetry is halfway between those zeros, at p=14. It goes through the vertex or point of maximum revenue.

The price for maximum revenue is p = 14 dollars.

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Mr. Wilson is giving his students a vocabulary test tomorrow over all the terms they have learned from this semester. Today, he
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1) The population

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2) The sample is every set of five cards that is selected by each student.

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Further, given that the cards are replaced every time all the students will face the same population when they are going to select a sample.
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8 0
2 years ago
A survey of 125 households was done to investigate whether households have laptops, tablets, or
riadik2000 [5.3K]

Answer:

3) 0.326

Step-by-step explanation:

Total Number of surveyed households =125

We want to determine the probability that a randomly selected household would have a laptop given that it does not  have a tablet.

Written in Probability notation: P(Laptop|No Tablet)

P(Laptop|No Tablet)=\dfrac{P(L\cap T')}{P(T')} \\=\dfrac{31/125}{95/125}\\=\dfrac{31}{95}\\\\=0.326

The correct option is C,

4 0
2 years ago
LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (-100,0) and (
Gre4nikov [31]

Answer:

\frac {(x)^{2}}{8100}+\frac {(y)^{2}}{1900}=1

Step-by-step explanation:

center of the hyperbola  is  (0,0)  = (h, k)

c = the distance form the center to either focal point  = 100

c^{2} =100^{2}=10000

The differences  from the receiver to the transmitters  =  2a

2a =  180  miles

a   =  180/2=90 miles

a^2 =90^{2}= 8100

b^{2}= c^{2} - a^{2}

b^{2}= 100^{2}-90^{2}=1900

b^{2}=1900

The standard form is

\frac {(x-h)^{2}}{a^{2}}+\frac {(y-k)^{2}}{b^{2}}=1

\frac {(x-0)^{2}}{a^{2}}+\frac {(y-0)^{2}}{b^{2}}=1

\frac {(x)^{2}}{8100}+\frac {(y)^{2}}{1900}=1

3 0
2 years ago
A water trough has two congruent isosceles trapezoids as ends and two congruent rectangles as sides.
BlackZzzverrR [31]

Answer:

Part a) The exterior surface area is equal to 160\ ft^{2}

Part b) The volume is equal to 240\ ft^{3}

Part c) The volume water left in the trough will be 84\ ft^{3}

Step-by-step explanation:

Part a) we know that

The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles

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<em>Find the area of two rectangles</em>

A=2[12*5]=120\ ft^{2}

<em>Find the area of two trapezoids</em>

A=2[\frac{1}{2}(8+2)h]

Applying Pythagoras theorem calculate the height h

h^{2}=5^{2}-3^{2}

h^{2}=16

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120\ ft^{2}+40\ ft^{2}=160\ ft^{2}

Part b) Find the volume

We know that

The volume is equal to

V=BL

where

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L is the length of the trough

we have

B=20\ ft^{2}

L=12\ ft

substitute

V=20(12)=240\ ft^{3}

Part c)

<em>step 1</em>

Calculate the area of the trapezoid for h=2 ft (the half)

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A=\frac{1}{2}(5+2)(2)=7\ ft^{2}

<em>step 2</em>

Find the volume

The volume is equal to

V=BL

where

B is the area of the trapezoidal face

L is the length of the trough

we have

B=7\ ft^{2}

L=12\ ft

substitute

V=7(12)=84\ ft^{3}

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2 years ago
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