Answer:
The proportion of student heights that are between 94.5 and 115.5 is 86.64%
Step-by-step explanation:
We have a mean and a standard deviation
. For a value x we compute the z-score as
, so, for x = 94.5 the z-score is (94.5-105)/7 = -1.5, and for x = 115.5 the z-score is (115.5-105)/7 = 1.5. We are looking for P(-1.5 < z < 1.5) = P(z < 1.5) - P(z < -1.5) = 0.9332 - 0.0668 = 0.8664. Therefore, the proportion of student heights that are between 94.5 and 115.5 is 86.64%
Answer:
Step-by-step explanation:
Given the following expresion provided in the exercise:
You can follow these steps in order to evaluate it when and
:
1. You need to substitute and
into the given expression:
2. Now you can solve the mutiplication:
3. Since , you get:
4. You must solve the division. Divide the numerator 16 by the denominator 4. Then:
5. And finally, you must solve the addition. So, you get this result:
Answer:
y = 0.2x + 250
Step-by-step explanation:
let the sales be x and y be earnings
thus,
given
x₁ = $3,500 ; y₁ = $950
and,
x₂ = $2,800 ; y₂ = $810
Now,
the standard line equation is given as:
y = mx + c
here,
m is the slope
c is the constant
also,
m =
or
m =
or
m = 0.2
substituting the value of 'm' in the equation, we get
y = 0.2x + c
now,
substituting the x₁ = $3,500 and y₁ = $950 in the above equation, we get
$950 = 0.2 × $3,500 + c
or
$950 = $700 + c
or
c = $250
hence,
The equation comes out as:
y = 0.2x + 250
Assuminhg the ark has a shoe-box (cuboid) shape it´s volume would be:
We have this three measurements () and it can be as simple as replacing them in the equation and solving but they are in all in
. We will convert them to
because the problem requires the answer in
. In order to do this we will use the given equivalences:
and another one:
First we will convert from cubits to palms:
now from to
:
now from to
:
We can calculate the Volume now like this:
The volume of trhe ark would be