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ser-zykov [4K]
2 years ago
7

A set of elementary school student heights are normally distributed with a mean of 105105105 centimeters and a standard deviatio

n of 777 centimeters. What proportion of student heights are between 94.594.594, point, 5 centimeters and 115.5115.5115, point, 5 centimeters? You may round your answer to four decimal places.
Mathematics
2 answers:
steposvetlana [31]2 years ago
4 0

Answer:

The proportion of student heights that are between 94.5 and 115.5 is 86.64%

Step-by-step explanation:

We have a mean \mu = 105 and a standard deviation \sigma = 7. For a value x we compute the z-score as (x-\mu)/\sigma, so, for x = 94.5 the z-score is (94.5-105)/7 = -1.5, and for x = 115.5 the z-score is (115.5-105)/7 = 1.5. We are looking for P(-1.5 < z < 1.5) = P(z < 1.5) - P(z < -1.5) = 0.9332 - 0.0668 = 0.8664. Therefore, the proportion of student heights that are between 94.5 and 115.5 is 86.64%

Elden [556K]2 years ago
4 0

Answer:

0.4247

Step-by-step explanation:

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A college statistics class conducted a survey of how students spend their money. They asked 25 students to estimate how much mon
anastassius [24]

Answer:

Option B, The mean will increase, but the median will remain the same.

Step-by-step explanation:

Given

Mean value is  31.52 dollars

Median Value is 32 dollar.

Mean is the average of all the units in a given set of data. Change in any of the number will change the mean.

Here the mean is 31.25

Total money would be 31.25 * 25 = 781.25\\

A number is changed from 2 to 20 , i.e addition of 18 dollars

the new mean would be 781.25 + 18/25 = 31.97

However, the median value is the value of the unit at the center of the arrangement. Hence, it will not change.

Option B is correct

7 0
2 years ago
1. A sample consists of 75 TV sets purchased several years ago. The replacement times of those TV sets have a mean of 8.2 years.
Greeley [361]

Answer:

8.2+/-0.25

= ( 7.95, 8.45) years

the 95% confidence interval (a,b) = (7.95, 8.45) years

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 8.2 years

Standard deviation r = 1.1 years

Number of samples n = 75

Confidence interval = 95%

z value(at 95% confidence) = 1.96

Substituting the values we have;

8.2+/-1.96(1.1/√75)

8.2+/-1.96(0.127017059221)

8.2+/-0.248953436074

8.2+/-0.25

= ( 7.95, 8.45)

Therefore the 95% confidence interval (a,b) = (7.95, 8.45) years

3 0
1 year ago
Mark and robyn used base-ten blocks to show that 200 is 100 times as much as 2. Whose model makes sense whose model is nonsense?
kiruha [24]

Answer:

Robyn model makes more sense and Mark's is nonsense

Step-by-step explanation:

In this question ,calculations not required .All we have to do is consider each model logically .

Marks

Marks model shows 20 rather than 2 which means 200 is 10 times as much as 20. It does not make any sense.

Robyn

Robyn model shows 2 which means 200 is 100 times as much as 2 and this is not only correct but also makes sense because 100 *2=200

4 0
2 years ago
If xy + 5ey = 5e, find the value of y'' at the point where x = 0.
notka56 [123]

Answer:

1 (only if e is not equal to 0)

Step-by-step explanation:

xy + 5ey = 5e

0y + 5ey = 5e

y = 5e/5e

y=1

6 0
2 years ago
PLEASE HELP!!!!!!!!! Ernest's friend rolls a six-sided number cube and lands on square 8. She asks Ernest to guess what number s
hjlf

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Step-by-step explanation:

7 0
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