Answer:
The correct answer is option b. "it has high face validity".
Explanation:
Face validity in a test is a very broad concept that simply refers to whether the test appears to be suitable to report what it claims to do. It is important to notice that high face validity in a test only means that the judgers of the test agree that the test is suitable, but it doesn't mean that the test is reliable for the patient and for the therapist. In this example, Kristoff should take other tests and examinations before he could be sure that he is not suffering from depression, particularly because he has many symptoms that indicate that he is depressed.
He is making a plant cell since the cell walls are box shaped, the balloon would be the large vacuole which takes up a lot of space in the cell, the marbles would be the ribosomes.
Answer:
See the explanation below, what is the question you intend to ask anyway?
Explanation:
- Meiosis transmit traits from one generation to the next. It the key process that brings genetic variation into the traits that offspring inherit from their parents. In the life cycle of an organism, meiosis is paired with the process of fertilization.
- Meiosis produces two daughter nuclei with the same number of chromosomes as the parent cell as each other.The chromosomes are re-grouped during meiosis to form new combinations of genes. Genetic reunion is very important as a source of genetic variation.
A
?
is most likely the answer
Answer:
36
Explanation:
A two-point test-cross is a cross between an individual with a double heterozygote genotype and a homo-zygous recessive individual in order to determine the recombination frequency between two linked genes. In genetics, one map unit (m.u.) can be defined as the measure of the distance (i.e., genetic distance instead of physical distance) between genes for which one (1) product of meiosis in one hundred (100) is recombinant. In this case, 36 of the offspring have the recombinant phenotype, while the remaining 64 offspring are not recombinant, and therefore both genes are separated by 36 mu (64 + 36 = 100 >> 36 mu).