Question

John runs 500 feet in 1 minute. Identify the correct conversion factor setup required to compute John's speed in inches per second.

Answer 1

Answer:

see the procedure

Step-by-step explanation:

Remember that

$1\ ft=12\ in$

To convert feet to inches multiply by 12

$1\ min=60\ sec$

To convert minutes to seconds multiply by 60

we have

$500\frac{ft}{min}=500(\frac{12}{60})=500(\frac{1}{5})=100\frac{in}{sec}$

Answer 2

Answer:

$\frac{500\text{ ft}}{\text{ 1 min}}\times \frac{1 \text{ min}}{\text{ 60 sec}}\times \frac{12\text{ inches}}{\text{1 ft}}$

Step-by-step explanation:

We have been given that John runs 500 feet in 1 minute. We are asked to identify the correct conversion factor setup required to compute John's speed in inches per second.              

We know that 1 minute equals 60 seconds and 1 feet equals 12 inches .

$\frac{500\text{ ft}}{\text{ 1 min}}\times \frac{1 \text{ min}}{\text{ 60 sec}}\times \frac{12\text{ inches}}{\text{1 ft}}$

Therefore, our required conversion factor would be $\frac{500\text{ ft}}{\text{ 1 min}}\times \frac{1 \text{ min}}{\text{ 60 sec}}\times \frac{12\text{ inches}}{\text{1 ft}}$.  

Let us covert 500 feet in 1 minute to inches per second as:

$\frac{500}{1}\times \frac{1}{\text{ 60 sec}}\times \frac{12\text{ inches}}{1}$

$\frac{500}{1}\times \frac{1}{\text{ 5 sec}}\times \frac{1\text{ inches}}{1}$

$\frac{500\text{ inches}}{\text{ 5 sec}}$

$\frac{100\text{ inches}}{\text{ sec}}$

Therefore, John runs at a rate of 100 inches per second.