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kkurt [141]
2 years ago
13

A piston having a diameter of 5.48 inches and a length of 9.50 in slides downward with a

Engineering
1 answer:
inna [77]2 years ago
4 0

Answer:

V = 4.585 \times 10^{-3}  ft/s

Explanation:

surface Area is given as = \pi dL

here , d is diameter of piston

L is distance travelled by the piston

a = \pi 5.48\times 9.5

velocity of piston

W = \mu A \frac{V}{t}

where,

w is weight of piston, \mu dynamic viscosity of fluid, t is thickness of fluid

0.5 = 0.016 \times \frac{163.55}{12^2} \frac{V}{\frac{0.002}{12}}

0.5 = 109.033 V

SOLVING FOR V

V = 4.585 \times 10^{-3}  ft/s

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A spherical tank for storing gas under pressure is 25 m in diameter and is made of steel 15 mm thick. The yield point of the mat
nalin [4]

Answer:

a) (option B) 230 kPa

b) (option A) 100 N/m

Explanation:

Given:

Diameter, d = 25 m

Thicknesses, t = 15 mm

Yield point = 240 MPa

Factor of safety = 2.5

a) To find the maximum internal pressure, let's use the formula:

\sigma l = \frac{\sigma y}{FOS} = \frac{PD}{4t}

\frac{\sigma y}{FOS} = \frac{PD}{4t}

Solving for P, we have:

P = \frac{\sigma y * 4t}{FOS * D}

P = \frac{240 * 4 * 15}{2.5 * 25}

P = 230.4 kPa

≈ 230 kPa

The maximum permissible internal pressure is nearly 230kPa

b) Given:

Thickness, t = 6.35 mm

L = 203 mm

Torque, T = 8 N m

Let's find the mean Area,

mA = (l - t)²

= (203 - 6.5)²

= 38671.22mm²

≈ 0.03867 m² (converted to meters)

To find the average shear flow, let's use the formula:

q = \frac{T}{2* mA}

= \frac{8}{2 * 0.03867}

q = 103.4 N/m approximately 100N/m

The average shear force flow is most nearly 100 N/m

4 0
2 years ago
Read 2 more answers
A well-insulated tank in a vapor power plant operates at steady state. Saturated liquid water enters at inlet 1 at a rate of 125
kompoz [17]

Answer:

a. The mass flow rate (in lbm/s) is 135lbm/s

b. The temperature (in o F) is 200.8°F

Explanation:

We assume that potential energy and kinetic energy are negligible and the control volume operates at a steady state.

Given

a. The mass flow rate (in lbm/s) is 135lbm/s

b.

m1 = Rate at inlet 1 = 125lbm/s

m2 = Rate at inlet 2 = 10lbm/s

The mass flow rate (in lbm/s) is calculated as m1 + m2

Mass flow rate = 125lbm/s + 10lbm/s

Mass flow rate = 135lbm/s

Hence, the mass flow rate (in lbm/s) is 135lbm/s

b. To calculate the temperature.

First we need to determine the enthalpy h1 at 14.7psia

Using table A-3E (thermodynamics)

h1 = 180.15 Btu/Ibm

h2 at 14.7psia and 60°F = 28.08 Btu/Ibm

Calculating h3 using the following formula

h3 = (h1m1 + h2m2) / M3

h3 = (180.15 * 125 + 28.08 * 10)/135

h3 = 168.8855555555555

h3 = 168.89 Btu/Ibm

To get the final temperature; we make use of table A-2E of thermodynamics.

Because h3 < h1, it means the liquid is at a compressed state.

The corresponding temperature at h3 = 168.89 is 200.8°F

The temperature (in o F) is 200.8°F

6 0
2 years ago
Which one of the following activities is not an example of incident coordination
Lady bird [3.3K]
Directing, ordering, or controlling
7 0
2 years ago
) A shaft encoder is to be used with a 50 mm radius tracking wheel to monitor linear displacement. If the encoder produces 256 p
andrey2020 [161]

Answer:

number of pulses produced =  162 pulses

Explanation:

give data

radius = 50 mm

encoder produces = 256 pulses per revolution

linear displacement = 200 mm

solution

first we consider here roll shaft encoder on the flat surface without any slipping

we get here now circumference that is

circumference = 2 π r .........1

circumference = 2 × π × 50

circumference = 314.16 mm

so now we get number of pulses produced

number of pulses produced = \frac{linear\ displacement}{circumference} × No of pulses per revolution .................2

number of pulses produced = \frac{200}{314.16} × 256

number of pulses produced =  162 pulses

5 0
2 years ago
what is the advantage of decreasing the field current of a separately excited dc motor below its nominal value
enyata [817]

Answer:

Ability to rotate at higher speeds

Explanation:

Constant K1 becomes greater than the other constant K2

This translates to that the motor being able to rotate at high speeds, without necessarily exceeding the nominal armature voltage.

The armature voltage is the voltage that is developed around the terminals of the armature winding of an Alternating Current, i.e AC or a Direct Current, i.e DC machine during the period in which it tries to generate power.

6 0
2 years ago
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