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love history [14]
2 years ago
11

A ramp leading into a building makes a 15o angle with the ground. the end of the ramp is 10 feet from the base of the building.

approximately how long is the ramp? round to the nearest tenth
Mathematics
1 answer:
Oksanka [162]2 years ago
3 0
We are tasked to solved for the length of the ramp having an inclination of 15 degrees with the ground and 10 feet from the end of the ramp to the base of the building of the ground. Using trigonometric properties, we have a formula given an angle and the its opposite sides which is,
sin(Angle)=opposite/hypothenuse
hypothenuse would be the distance or the length of the ramp.
so we have,
sin(15)=10/hypothenuse
Cross-multiply, we have,
hypothenuse=10/sin(15)
using scientific calculator having a DEG mode,
hypothenuse=38.63703
Rounding of in nearest tenth we get,
hypothenuse=38.6 ft
Therefore, the ramp is 38.6 ft long
You might be interested in
Is 5/21 rational or irrational number ?
ZanzabumX [31]

Answer:

rational

Step-by-step explanation:

irrational numbers can not be expressed as a fraction

6 0
2 years ago
A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $4 more than t
belka [17]

system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y is  x+8y=68 and 3x+4y=64   .

<u>Step-by-step explanation:</u>

Here we have , A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $4 more than the first customer for 1 large candle and 8 small candles. The price of each large candle is the same, and the price of each small candle is the same. We need to find Which system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y . Let's find out:

Let the price in dollars of each large candle, x, and each small candle, y .So

A customer at a store paid $64 for 3 large candles and 4 small candles

Equation is  :

⇒ 3x+4y=64  .....(1)

At the same store, a second customer paid $4 more than the first customer for 1 large candle and 8 small candles.

Equation is  :

⇒ x+8y=68  .......(2)

3(2)-(1) i.e.

⇒ 3(x+8y)-(3x+4y)=68(3)-64

⇒ 20y=140

⇒ y=7

So , x+8y=68  

⇒  x+8(7)=68

⇒  x=12

Therefore , system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y is  x+8y=68 and 3x+4y=64   .

7 0
2 years ago
We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys
marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation    

\bar X=19.2 represent the battery life sample mean    

\sigma=2.5 represent the population standard deviation    

n=25 sample size    

\mu_o =18 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:    

Null hypothesis:\mu = 18    

Alternative hypothesis:\mu \neq 18    

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis:\mu \leq 18    

Alternative hypothesis:\mu > 18  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4    

4) P-value    

First we need to calculate the degrees of freedom given by:  

df=n-1=25-1=24  

Since is a two tailed test for parts I and II, the p value would be:    

p_v =2*P(t_{(24)}>2.4)=0.0245

And for part III since we have a one right tailed test the p value is:

p_v =P(t_{(24)}>2.4)=0.0122

5) Conclusion    

I. This finding is significant for a two-tailed test at .05.

Since the p_v. We reject the null hypothesis so we don't have a significant result. FALSE

II. This finding is significant for a two-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

6 0
2 years ago
The first three terms of an arithmetic series are 6p+2, 4p²-10 and 4p+3 respectively. Find the possible values of p. Calculate t
Doss [256]

Answer:

First Case:

\displaystyle p=\frac{5}{2}\text{ and } d=-2

Second Case:

\displaystyle p=-\frac{5}{4}\text{ and } d=\frac{7}{4}

Step-by-step explanation:

We know that the first three terms of an arithmetic series are:

6p+2, 4p^2-10, \text{ and } 4p+3

Since this is an arithmetic sequence, each subsequent term is <em>d</em> more than the previous term, where <em>d</em> is our common difference.

Therefore, we can write the second term as;

4p^2-10=(6p+2)+d

And, likewise, for the third term:

4p+3=(6p+2)+2d

Let's solve for <em>d</em> for each of the equations.

Subtracting in the first equation yields:

d=4p^2-6p-12

And for the second equation:

2d=-2p+1

To avoid fractions, let's multiply the first equation by 2. Hence:

2d=8p^2-12p-24

Therefore:

8p^2-12p-24=-2p+1

Simplifying yields:

8p^2-10p-25=0

Solve for <em>p</em>. We can factor:

8p^2+10p-20p-25=0

Factor:

2p(4p+5)-5(4p+5)=0

Grouping:

(2p-5)(4p+5)=0

Zero Product Property:

\displaystyle p_1=\frac{5}{2} \text{ or } p_2=-\frac{5}{4}

Then, we can use the second equation to solve for <em>d</em>. So:

2d_1=-2p_1+1

Substituting:

\begin{aligned} 2d_1&=-2(\frac{5}{2})+1 \\ 2d_1&=-5+1 \\ 2d_1&=-4 \\ d_1&=-2\end{aligned}

So, for the first case, <em>p</em> is 5/2 and <em>d</em> is -2.

Likewise, for the second case:

\begin{aligned} 2d_2&=-2(-\frac{5}{4})+1 \\ 2d_2&=\frac{5}{2}+1 \\ 2d_2&=\frac{7}{2} \\ d_2&=\frac{7}{4}\end{aligned}

So, for the second case, <em>p </em>is -5/4, and <em>d</em> is 7/4.

By using the values, we can determine our series.

For Case 1, we will have:

17, 15, 13.

For Case 2, we will have:

-11/2, -15/4, -2.

8 0
1 year ago
If a cone with a diameter of 10 meters has a surface area of 290.6 square meters, find its slant height.
Finger [1]
<h2>Hello!</h2>

The answer is:

The slant height is 13.43 m.

l=13.43m

<h2>Why?</h2>

To solve the problem, we need to use the following equations to calculate the total surface area and the lateral surface area of right cone:

TotalSurfaceArea=LateralSurfaceArea+BaseArea

LateralSurfaceArea=\pi *r*l

Where,

r, is the radius of the cone.

l, is the slant height of the cone.

We are given the following information:

TotalSurfaceArea=290.6m^{2} \\Diameter=10m\\Radius=\frac{1}{2}d=\frac{1}{2}10m=5m

So, calculating the area of the base(circle) in order to find the lateral surface area, we have:

BaseArea=\pi *r^{2} \\\\BaseArea=\pi *5m^{2} =\pi *25m^{2}=79.54m^{2}

Then, substituting the area of the base into the total surface area to calculate the surface area of the cone, we have:

LateralSurfaceArea=TotalSurfaceArea-BaseArea

LateralSurfaceArea=290.6m^{2}-79.54m^{2}

LateralSurfaceArea=211.06m^{2}

Now, calculating the slant height, we have:

LateralSurfaceArea=\pi *r*l

l=\frac{LateralSurfaceArea}{\pi*r }

Substituting, we have:

l=\frac{211.06m^{2}}{\pi*5 }=\frac{211.06}{15.71m }

l=\frac{211.06}{15.71m }=13.43m

Hence, we have that the slant height is 13.43 m.

l=13.43m

Have a nice day!

6 0
2 years ago
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