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2 years ago

13

In a water molecule, shared electons spend more time around th oxygen atom than the hydrogen atoms. as a result, the oxygen atom

is...

1 answer:

Tasya [4]2 years ago

5 0

The oxygen atom has a partial negative charge. Due to the shared electrons spending more time in this region.

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If the pressure P applied to a gas is increased while the gas is held at a constant temperature, then the volume V of the gas wi

yuradex [85]

Answer:

For these types of questions the equation that we must take into account is that:

T = PxV (where T is the temperature, P is the pressure and V is the volume) this equation is described as we consider that this is the value N and R is 1, therefore it is not necessary to explain them now.

Explanation:

The quoted equation refers to Boyle's Law, in this law we can explain that the volume increases if the pressure decreases and if the temperature also increases, if the pressure increases and the volume decreases this means that the gas is compressing assuming that the temperature is constant

8 0

2 years ago

Read 2 more answers

The practical limit to ages that can be determined by radiocarbon dating is about 41000-yr-old sample, what percentage of the or

Aloiza [94]

Answer:

In percentage, the sample of C-4 remains = 0.7015 %

Explanation:

The Half life Carbon 14 = 5730 year

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac {ln\ 2}{t_{1/2}}$

$k=\frac {ln\ 2}{5730}\ hour^{-1}$

The rate constant, k = 0.000120968 year⁻¹

Time = 41000 years

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

So,

$\frac {[A_t]}{[A_0]}=e^{-0.000120968\times 41000}$

$\frac {[A_t]}{[A_0]}=0.007015$

<u>In percentage, the sample of C-4 remains = 0.7015 %</u>

3 0

2 years ago

at what temperature (inc) would the volume a gas be equal to 45.7L if the volume of gas was 33.9L at 12.4c

vesna_86 [32]

Answer:

The answer to your question is T1 = 384.7 °K

Explanation:

Data

Volume 1 = V1 = 45.7 l

Temperature 1 = T1 = ?

Volume 2 = V2 = 33.9 l

Temperature 2 = T2 = 12.4°C

To solve this problem use Charles' law

V1/T1 = V2/T2

T1 = V1T2/V2

-Convert temperature to °K

T2 = 12.4 + 273 = 285.4°K

-Substitution

T1 = (45.7 x 285.4) / 33.9

-Simplification

T1 = 13042.8 / 33.9

-Result

T1 = 384.7 °K

7 0

2 years ago

What do you think happens to Difluoroethane at –24°C? Provide evidence to support your claim.

balandron [24]

Answer:

The following subsections explain the explanation according to the particular circumstance.

Explanation:

The boiling point seems to be the temperature beyond which the working fluid as well as the boiling phase would be at a predetermined pressure or voltage at equilibrium among one another and.
The vapor or boiling temperature of 1,1 difluoroethane seems to be -25oC at 1 atm, although as a gas it can remain at a higher temperature around -24oC.

6 0

2 years ago

Consider the equilibrium reaction: 3CIO-(aq) ↔ CIO3-(aq) + 2CI-(aq) The equilibrium constant Kc = 3.2 x 103. The following conce

blagie [28]

Answer:

Forward direction

Explanation:

The reaction quotient of an equilibrium reaction measures relative amounts of the products and the reactants present during the course of the reaction at particular point in the time.

Q < Kc , reaction will proceed in forward direction.

Q > Kc , reaction will proceed in backward direction.

Q = Kc , reaction at equilibrium.

It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The concentration of the liquid and the gaseous species does not change and thus is not written in the expression.

Thus, for the reaction:

$3CIO^{-}_{(aq)}\rightleftharpoons CIO_3^{-}_{(aq)}+2Cl^{-}$

The expression is:

$Q=\frac {[CIO_3^{-}][Cl^{-}]^2}{[CIO^{-}]^3}$

Given,

[Cl⁻] = 0.50 mol/L; [ClO₃⁻] = 0.32 mol/L; [ClO⁻] = 0.24 mol/L

So,

$Q=\frac{0.32\times (0.50)^2}{(0.24)^3}$

Q = 5.7870

Since, Q < Kc ( $3.2\times 10^3$ )

The reaction will go in forward direction.

6 0

2 years ago