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lozanna [386]
2 years ago
5

If the pressure P applied to a gas is increased while the gas is held at a constant temperature, then the volume V of the gas wi

ll decrease. The rate of change of the volume of gas with respect to the pressure is proportional to the reciprocal of the square of the pressure. Which of the following is a differential equation that could describe this relationship?
Chemistry
2 answers:
yuradex [85]2 years ago
8 0

Answer:

For these types of questions the equation that we must take into account is that:

T = PxV (where T is the temperature, P is the pressure and V is the volume) this equation is described as we consider that this is the value N and R is 1, therefore it is not necessary to explain them now.

Explanation:

The quoted equation refers to Boyle's Law, in this law we can explain that the volume increases if the pressure decreases and if the temperature also increases, if the pressure increases and the volume decreases this means that the gas is compressing assuming that the temperature is constant

navik [9.2K]2 years ago
3 0

Answer:

A differential equation that could describe the relationship of the rate of change of the volume of gas with respect to the pressure is;

V' = -\frac{C}{P^2}.

Explanation:

Boyle's law states that at constant temperature, the pressure of a given mass of gas is inversely proportional to its volume.

That is;

P₁×V₁ = P₂×V₂ or

P×V = Constant, C

That is V = \frac{C}{P}

Therefore, the rate of change of volume of a gas is given as

\frac{dV}{dt} = -\frac{C}{P^2} \frac{dP}{dt} which gives

\frac{dV}{dt} \times \frac{dt}{dP}= \frac{dV}{dP} = -\frac{C}{P^2}

That is the rate of change of the volume of gas with respect to the pressure is proportional to the reciprocal of the square of the pressure.

\frac{dV}{dP} = -\frac{C}{P^2}.

V' = -\frac{C}{P^2}.

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Answer:

0.125 mole

Explanation:

From Avogadro's hypothesis, we discovered that 1 mole of any substance contains 6.02x10^23 atoms.

The statement above suggests that 1 mole of chromium contains 6.02x10^23 atoms.

Now, if 1mole of of chromium contains 6.02x10^23 atoms,

Then Xmol of chromium contains 7.52x10^22 atoms i.e

Xmol of chromium = 7.52x10^22/6.02x10^23

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2 years ago
At 900.0 K, the equilibrium constant (Kp) for the following reaction is 0.345. 2SO2 + O2(g) → 2SO3(g) At equilibrium, the partia
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Answer:

The partial pressure of SO₃ is 82.0 atm

Explanation:

The equilibrium constant Kp is equal to <em>the equilibrium pressure of the gaseous products raised to the power of their stoichiometric coefficients divided by the equilibrium pressure of the gaseous reactants raised to the power of their stoichiometric coefficients</em>.

For the reaction,

2 SO₂(g) + O₂(g) → 2 SO₃(g)

Kp = 0.345 = \frac{(pSO_{3})^{2} }{(pSO_{2})^{2} \times pO_{2} }\\pSO_{3} = \sqrt[]{0.345 \times (pSO_{2})^{2} \times pO_{2} } \\pSO_{3} = \sqrt[]{0.345 \times (35.0)^{2} \times 15.9 } \\pSO_{3} = 82.0 atm

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Which pair of statements below is correct? Multiple Choice An octet is formed via ionic bonding when one or more valence electro
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Answer:

An octet is formed via ionic bonding when one or more valence electrons are transferred from one atom to another.

An octet is formed via covalent bonding when valence electrons are shared between atoms.

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K - 0.779 g / 39 g/mol
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O₂ moles = 0.638 g / 32 g/mol
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Answer:

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