Zachary weighs 37 kilograms 95 grams. Gabe weighs 4,650 grams less than Zachary. Harry weighs 2,905 grams less than Gabe. How mu
1 answer:
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Answer:
She sells 4 loaves of bread
Step-by-step explanation:
Lets explain how to solve the problem
→ A baker uses cups of flour to make bread
→ She uses cups of flour to make each loaf
From these information we can find the number of loaves of bread
she can make
∵ There are cups of flour
∵ Each loaf of bread needs cups of flour
∴ The number of loaves = ÷
To divide two mixed numbers make them improper fractions and
change the division sign to multiplication sign and reciprocal the
fraction after the division sign
∵ =
∴ =
∵ =
∴ =
∴ The number of loaves = ×
∴ The number of loaves = 6
<em>She can make 6 loaves</em>
→ The baker sells of the loaves of bread that she makes
→ We need to find the number of loves of bread she sells
∵ She sells of the loaves
∵ There are 6 loves
∴ The number of loaves she sells = 6 × = 4
<em>She sells 4 loaves of bread</em>
Answer:
<em>H₀</em>: <em>μ</em>₁ = <em>μ</em>₂ vs, <em>Hₐ</em>: <em>μ</em>₁ > <em>μ</em>₂.
Step-by-step explanation:
A two-sample <em>z</em>-test can be performed to determine whether the claim made by the owner of pier 1 is correct or not.
It is provided that the weights of fish caught from pier 1 and pier 2 are normally distributed with equal population standard deviations.
The hypothesis to test whether the average weights of the fish in pier 1 is more than pier 2 is as follows:
<em>H₀</em>: The weights of fish in pier 1 is same as the weights of fish in pier 2, i.e. <em>μ</em>₁ = <em>μ</em>₂.
<em>Hₐ</em>: The weights of fish in pier 1 is greater than the weights of fish in pier 2, i.e. <em>μ</em>₁ > <em>μ</em>₂.
The significance level of the test is:
<em>α</em> = 0.05.
The test is defined as:
The decision rule for the test is:
If the <em>p</em>-value of the test is less than the significance level of 0.05 then the null hypothesis will be rejected and vice-versa.