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2 years ago

Can a quadratic polynomial equation with real coefficients have one real solution and one complex solution? If so,

Mathematics

1 answer:

Anastasy [175]2 years ago

5 0

Answer:

Step-by-step explanation:

We have to find that a quadratic polynomial equation with real coefficient can have one real solution and one complex solution.

quadratic equation is given by

$ax^2+bx+c=0$

It can be written as the product of linear factors

$ax^2+bx+c=a(x-r_1)(x-r_2)$

Where $r_1,r_2$ are solutions of the given polynomial equation.

No , a quadratic polynomial equation can not have one real solution and one complex solution because complex root are always in paired not a single.

A quadratic equation have two roots only.

If a quadratic equation have complex root then the equation have both complex root .

If a equation have real root then it have both real.

Therefore, a quadratic equation can not have one real and one compelx solution.

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Maria will spin the arrow on the spinner 2 times. What is the probability that the arrow will stop on the same letter twice? 19

gavmur [86]

Suppose the spinner lands on a. There's a 1/3 chance that it'll land on a the second time.
Suppose the spinner lands on b. There's a 1/3 chance that it'll land on b the second time.
Suppose the spinner lands on c. There's a 1/3 chance that it'll land on c the second time.

We've covered all possibilities for the first spin, and they're all equal, so their average is 1/3.

The probability that it'll land on the same letter twice is 33.3%.

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2 years ago

A rectangle’s length is 2 units more than twice its width. Its area is 40 square units. The equation w(2w + 2) = 40 can be used

barxatty [35]

I hope this helps you

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2 years ago

Read 3 more answers

The frequency distribution below represents the rents of 250 randomly selected federally subsidized apartments in Washington D.C

Naily [24]

Answer:

92%

Step-by-step explanation:

The percentage of apartments rented for less than $600 is given by the sum of all of the apartments in the 300 to 400, 400 to 500 and 500 to 600 intervals divided by the total number of apartments sampled (250).

$P(X$

92% of the apartments rented for less than $600.

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2 years ago

Determine if this conjecture is true. If not, give a counterexample. The difference of two negative numbers is a negative number

Orlov [11]

That would be a false statement

6 0

2 years ago

Estimate the indicated probability by using normal distribution as an approximation to the binomial distribution. Estimate P(6)

lianna [129]

Answer:

P(6) = 0.6217

Step-by-step explanation:

To find P(6), which is the probability of getting a 6 or less, we will need to first calculate two things: the mean of the sample (also known as the "expected value") and the standard deviation of the sample.

Mean = np

Here, "n" is the sample size and "p" is the probability of the outcome of interest, which could be getting a heads when a tossing a coin, for instanc

So, Mean = n × p = (18) ×(0.30) = 5.4

Next we we will find the standard deviation:

Standard Deviation = $\sqrt{npq}$

n = 18 and p = 0.3 "q" is simply the probability of the other possible outcome (maybe getting a tails when flipping a coin), so q = 1 - p

Standard Deviation = $\sqrt{npq} = \sqrt{(18)(0.3)(0.7)}$

= 1.944

Now calculate the Z score for 6 successes.

Z = ( of successes we're interested in - Mean) ÷ (Standard Deviation)

=(6-5.4) ÷ (1.944) = 0.309

we have our Z-score, we look on the normal distribution and find the area of the curve to the left of a Z value of 0.309. This is basically adding up all of the possibilities for getting less than or equal to 6 successes. So, we get 0.6217.

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2 years ago