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mote1985 [20]
2 years ago
12

The frequency distribution below represents the rents of 250 randomly selected federally subsidized apartments in Washington D.C

.
Rents in $$$ Frequency
300 but less than 400 113
400 but less than 500 85
500 but less than 600 32
600 but less than 700 16
700 but less than 800 4
What percentage of the apartments rented for less than $600?
Mathematics
1 answer:
Naily [24]2 years ago
5 0

Answer:

92%

Step-by-step explanation:

The percentage of apartments rented for less than $600 is given by the sum of all of the apartments in the 300 to 400, 400 to 500 and 500 to 600 intervals divided by the total number of apartments sampled (250).

P(X

92% of the apartments rented for less than $600.

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For the binomial expansion of (x + y)^10, the value of k in the term 210x 6y k is a) 6 b) 4 c) 5 d) 7
Sloan [31]

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Step-by-step explanation:

Expanding the polynomial using the formula:

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$\binom{n}{k}=\frac{n!}{(n-k)!k!}$

I think you mean 210x^6y^4

We can deduce that this term will be located somewhere in the middle. So I will calculate k= 5; k=6 \text{ and } k =7.

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$\binom{10}{5} (y)^{10-5} (x)^{5}=\frac{10!}{(10-5)! 5!}(y)^{5} (x)^{5}= \frac{10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5! }{5! \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 } \\ =\frac{30240}{120} =252 x^{5} y^{5}$

Note that we actually don't need to do all this process. There's no necessity to calculate the binomial, just x^{n-k} y^k

For k=6

$\binom{10}{6} \left(y\right)^{10-6} \left(x\right)^{6}=\frac{10!}{(10-6)! 6!}\left(y\right)^{4} \left(x\right)^{6}=210 x^{6} y^{4}$

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