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AVprozaik [17]
2 years ago
14

What is the solution of the system x − 3y = –13 and 5x + 7y = 34? A. `x = (6)/(5)`, y = 4 B. `x = (7)/(2), y = (9)/(2)` C. `x =

(1)/(2), y = (9)/(2)` D. x = –3, y = 7
Mathematics
2 answers:
Masteriza [31]2 years ago
5 0

For this case we have the following system of equations:

x-3y = -13\\5x + 7y = 34

From the first equation we clear "x":

x = -13 + 3y

We substitute in the second equation:

5 (-13 + 3y) + 7y = 34

We apply distributive property:

-65 + 15y + 7y = 34

We add similar terms:

-65 + 22y = 34

We add 65 to both sides:

22y = 34 + 65\\22y = 99

We divide between 22 on both sides:

y = \frac {99} {22}\\y = \frac {9} {2}

We look for the value of the variable "x":

x = -13 + 3 \frac {9} {2}\\x = -13 + \frac {27} {2}\\x = \frac {-26 + 27} {2}\\x = \frac {1} {2}

Thus, the solution of the system is:

(x, y): (\frac {1} {2}, \frac {9} {2})

ANswer:

(x, y): (\frac {1} {2}, \frac {9} {2})

Anna71 [15]2 years ago
4 0

Answer:

C. X=1/2, Y=9/2

Step-by-step explanation:

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Farmer frank owns a piece of grassland. The grass grows at a constant rate and each cow eats at a constant rate. 12 cows can eat
MrRa [10]

Answer: There are 36 cows that can eaten 72 acres of grass in 126 days.

Step-by-step explanation:

Let x be the amount of grass in an acre initially.

Let y be the amount of grass grown in an acre per day.

Since we have given that

12 cows can eat 10 acres of grass in 28 days

12×28  = 10x + 10×28 y

336 = 10x + 280 y----------------------------(1)

Similarly,

21 cows can eat 30 acres of grass in 63 days.

21×63  = 30x + 30×63 y

1323 = 30x +1890 y ---------------------------(2)

So, by graphing method, we get the value of x and y

x=\dfrac{126}{5},\ y=\dfrac{3}{10}

So, we have,  72 acres of grass in 126 days, we need to find the number of cows.

So, it becomes,

c×126 = 72x + 72×126 y

126c=72\times \dfrac{126}{5}+72\times 126\times \dfrac{3}{10}\\\\126x=4536\\\\x=\dfrac{4536}{126}\\\\x=36

Hence, there are 36 cows that can eaten 72 acres of grass in 126 days.

3 0
2 years ago
g In a survey of 500 residents, 300 were opposed to the use of the photo-cop for issuing traffic tickets.The standard error of t
Evgesh-ka [11]

Answer:

Z-score 1.96

Margin of error d= 0.04323

Step-by-step explanation:

Hello!

The study variable in this case is

X: Number of people that oppose the use of photo-cop for issuing traffic tickets in a sample of 500.

n= 500

The parameter of interest is the proportion of people that opposes it.

The estimated proportion is p'= 300/500= 0.6

To estimate the population proportion per Confidence interval you have to approximate the distribution of the sample proportion p' to normal:

p'≈N(p;p(1-p)1/n)

The mean of this distribution is p and the variance is p*(1-p)*1/n

To construct the Confidence interval, since the value of the population proportion is unknown, an estimated variance is used:

p'(1-p')*1/n ⇒ then the estimated standard error is √(p'(1-p')*1/n)

The formula for the confidence interval is:

p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

Where "Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }" represents the margin of error of the interval.

Now for a confidence level of 0.95 the value of Z is Z_{0.975}= 1.965

The estimated standard error is already calculated: \sqrt{\frac{p'(1-p')}{n} } = 0.022

The margin of error (d) is then:

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }= 1.965 * 0.022

d= 0.04323

I hope it helps!

7 0
2 years ago
Courtney has a total of 88 stamps worth $15.56. Some are 25 cent stamps and some 2 cent stamps. How many of each does she have
Oksi-84 [34.3K]
<span>88 stamps -------------------- >  $15.56
A------------------------------>number of  </span>stamps ------------ ><span>25 cent
B----------------------------- > </span>number of  stamps ------------ >2 cent

A+B=88------------------ > A=88-B
0.25A+.02B=15.56
resolving
0.25(88-B)+0.02B=15.56
22-0.25B+0.02B=15.56
-0.23B=-6.44----------------------- > B=28 stamps of 2 cent
A=88-B-- >88-28=60------------- > A=60 stamps of 25 cent
6 0
2 years ago
Read 2 more answers
Which congruence theorems can be used to prove ΔEFG ≅ ΔJHG? Select two options.
mezya [45]
<h2><u><em>Answer: </em></u></h2><h2><u><em> </em></u></h2>

ASA  and AAS

<h2><u><em>Step-by-step explanation: </em></u></h2>

We do not know if these are right triangles; therefore we cannot use HL to prove congruence.

We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.

We are given that EF is parallel to HJ.  This makes EJ a transversal.  This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent.  We also know that ∠EGF and ∠HGJ are vertical angles and are congruent.  This gives us two angles and a non-included side, which is the AAS congruence theorem.

Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent.  Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.

5 0
2 years ago
Read 2 more answers
What is the difference between 903.55 and 87.7<br>​
vitfil [10]

Answer:903.55

Step-by-step explanation:

6 0
2 years ago
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