Answer:
28
Step-by-step explanation:
Given that 12.5% of students own at least 1 pet, then the percentage of students who do not own a pet is
100% - 12.5% = 87.5%
Calculate 87.5% of 32, that is
× 32
= 0.875 × 32 = 28 ← number of students who do not own a pet
Question:
You are in a bike race. When you get to the first checkpoint, you are 2/5 of the distance to the second checkpoint. When you get to the second check point, you are 1/4 of the distance to the finish. If the entire race is 40 miles, what is the distance between the start and the first check point?
Answer: 4 miles
Step-by-step explanation:
Let distance between start to first checkpoint = x
First checkpoint to second checkpoint = 2/5 of x
Distance of start to checkpoint 1 = ( 2/5 of start to checkpoint 2)
Distance of start to checkpoint 2 = (1/4 of start to finish)
If start to checkpoint 2 = 1/4 of start to finish
Then,
Distance of start to checkpoint 1 = ( 2/5 * 1/4 of start to finish)
Distance of start to checkpoint 1 = 2/20 of start to finish = 1/10 of start to finish
Entire race = 40 miles = distance from start to finish
1/ 10 of 40
= ( 1/10) × 40
= 4 miles
Answer:
13,8%
Step-by-step explanation:
There are six employees and six cheks, so there are 36 (6x6) possible combinations so if we need to measure the probability that five of them receive the exact check is only one for each one of them over the 36 possibilities, so 1/36 for one plus 1/36 the second and so on. 5/36 = 13,8%.
Answer:
Step-by-step explanation:
The mentioned relationship for the weight, in pounds, of the kitten with respect to time, in weeks, is

Weight of the kitten after 10 weeks

pounds
This modeled equation is based on the observation of the early age of a kitten where the kitten is in its growth period, but in the early stage the growth rate in the weight of the kitten was the same but the growth of any living beings continues till the adult stage. So, after some time, in real life situation, this weekly change in weight will become zero, So, this model is not suitable to measure the weight of the kitten over the larger time period.
Here, t= 10 weeks is nearby the observed time period, so the linearly modeled equation can be used to predict the weight.
Hence, the weight of the kitten after 10 weeks is 16.5 pounds.
She will need 12 seconds because -20•12=-240