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AVprozaik [17]
2 years ago
14

What is the solution of the system x − 3y = –13 and 5x + 7y = 34? A. `x = (6)/(5)`, y = 4 B. `x = (7)/(2), y = (9)/(2)` C. `x =

(1)/(2), y = (9)/(2)` D. x = –3, y = 7
Mathematics
2 answers:
Masteriza [31]2 years ago
5 0

For this case we have the following system of equations:

x-3y = -13\\5x + 7y = 34

From the first equation we clear "x":

x = -13 + 3y

We substitute in the second equation:

5 (-13 + 3y) + 7y = 34

We apply distributive property:

-65 + 15y + 7y = 34

We add similar terms:

-65 + 22y = 34

We add 65 to both sides:

22y = 34 + 65\\22y = 99

We divide between 22 on both sides:

y = \frac {99} {22}\\y = \frac {9} {2}

We look for the value of the variable "x":

x = -13 + 3 \frac {9} {2}\\x = -13 + \frac {27} {2}\\x = \frac {-26 + 27} {2}\\x = \frac {1} {2}

Thus, the solution of the system is:

(x, y): (\frac {1} {2}, \frac {9} {2})

ANswer:

(x, y): (\frac {1} {2}, \frac {9} {2})

Anna71 [15]2 years ago
4 0

Answer:

C. X=1/2, Y=9/2

Step-by-step explanation:

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Answer:

The total number of slices is 92

Step-by-step explanation:

we know that

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step 1

30% of the pizzas have 12 slices each

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0.30(10)=3 pizzas

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step 2

70% of the pizzas have 8 slices each

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-7

Step-by-step explanation:

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An elevator went up 15 floors, down 9 floors, up 11 floors and down 19 floors. Find the net change
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It went up 26, down 28, a net change of down 2.
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A library buys 36 English books, 48 Science books and 72 Mathematics books. The thickness of each book is the same. Now, the lib
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13

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The GCF of 36, 48, and 72 is 12 so there will be 36 / 12 = 3 stacks of English books, 48 / 12 = 4 stacks of science books and 72 / 12 = 6 stacks of math books for a total of 3 + 4 + 6 = 13 stacks.

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Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
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Answer:

Step-by-step explanation:

(a)

The bid should be greater than $10,000 to get accepted by the seller. Let bid x be a continuous random variable that is uniformly distributed between

$10,000 and $15,000

The interval of the accepted bidding is [ {\rm{\$ 10,000 , \$ 15,000}], where b = $15000 and a = $10000.

The interval of the provided bidding is [$10,000,$12,000]. The probability is calculated as,

\begin{array}{c}\\P\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{12000}^{15000}\\\end{array}

=1- \frac{[15000-12000]}{5000}\\\\=1-0.6\\\\=0.4

(b)  The interval of the accepted bidding is [$10,000,$15,000], where b = $15,000 and a =$10,000. The interval of the given bidding is [$10,000,$14,000].

\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)

=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8

(c)

The amount that the customer bid to maximize the probability that the customer is getting the property is calculated as,  

The interval of the accepted bidding is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The interval of the given bidding is [$10,000,$15,000].

\begin{array}{c}\\f\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\\\\{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\\\\{\rm{ = 1}}\\\end{array}

(d)  The amount that the customer bid to maximize the probability that the customer is getting the property is $15,000, set by the seller. Another customer is willing to buy the property at $16,000.The bidding less than $16,000 getting considered as the minimum amount to get the property is $10,000.

The bidding amount less than $16,000 considered by the customers as the minimum amount to get the property is $10,000, and greater than $16,000 will depend on how useful the property is for the customer.

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