Answer : Remaining two observation becomes 97 and 107.
Explanation :
Since we have given that
Mean = 100
Modal value = 98
Range = 10
As we know that ,
Range = Highest-Lowest
Let highest observation be x
Let lowest observation be y
So equation becomes x-y=10 ----equation 1
So, observation becomes
x,98,98,y
Now, we use the formula of mean i.e.
Mean = 
So, mean =
So our 2nd equation becomes
x+y=204
On using elimination method of system of linear equation on these two equation we get,
x=97
and

Hence , remaining two observation becomes 97 and 107.
Answer:
48 hats and 104 shirts
Step-by-step explanation:
These are the equations you build from the problem:
h + s = 152
8.50h + 12s = 1656
This is how I solved them:
s= 152-h
8.5h + 12(152-h) = 1656
8.5h + 1824 - 12h = 1656
Solve for h
h= 48
Put this into first equation (h +s = 152) to get s
Answer:
a. 440
Step-by-step explanation:
The information provided allows us to set up the following system of linear equations:

We already have the value for A, solving the system gives us the values for B and C:

The total number of forms used is:

He used 440 forms.
probability that a dessert sold at a certain cafe contains chocolate is 86%.
The probability that a dessert containing chocolate also contains nuts is 30%.
Find the probability that a dessert chosen at random contains nuts given that it contains chocolate
P(nuts given chocolate) = .30/.86 = .349 or 34