Answer:
The answer is 3√5 mi.
The formula is: d = √(3h/2)
Wyatt:
h = 120 ft
d = √(3 * 120/2) = √180 = √(36 * 5) = √36 * √5 = 6√5 mi
Shawn:
h = 270 ft
d = √(3 * 270/2) = √405 = √(81 * 5) = √81 * √5 = 9√5 mi
How much farther can Shawn see to the horizon?
Shawn - Wyatt = 9√5 - 6√5 = 3√5 mi
Answer:
AB parallel to CD because both lines have a slope of
of 4/3
Step-by-step explanation:
The question is not complete, there is no graph.
A graph for the question is attached below.
From the image attached below, line 1 passes through points A = (-3, -3) and point B = (0, 1) while line 2 passes through point C = (0, -5) and point D = (3, -1).
Two parallel are said to be parallel if the have the same slope. The slope of a line passing through points:

Line 1 passes through points A = (-3, -3) and point B = (0, 1), the slope of line 1 is:

Line 2 passes through point C = (0, -5) and point D = (3, -1). the slope of line 2 is:

Therefore AB parallel to CD because both lines have a slope of
of 4/3
Answer:
The value of x that gives the maximum transmission is 1/√e ≅0.607
Step-by-step explanation:
Lets call f the rate function f. Note that f(x) = k * x^2ln(1/x), where k is a positive constant (this is because f is proportional to the other expression). In order to compute the maximum of f in (0,1), we derivate f, using the product rule.

We need to equalize f' to 0
- k*(2x ln(1/x) - x) = 0 -------- We send k dividing to the other side
- 2x ln(1/x) - x = 0 -------- Now we take the x and move it to the other side
- 2x ln(1/x) = x -- Now, we send 2x dividing (note that x>0, so we can divide)
- ln(1/x) = x/2x = 1/2 ------- we send the natural logarithm as exp
- 1/x = e^(1/2)
- x = 1/e^(1/2) = 1/√e ≅ 0.607
Thus, the value of x that gives the maximum transmission is 1/√e.