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just olya [345]
2 years ago
11

Three brothers Adam, Paul, and Jake are standing on a large carnival scale. The total weight for all three boys reads 180 pounds

on the scale. The ratio of the weights between Adam and Jake is 2:3. If Jake weighs 60 pounds, how much does paul weigh?
Mathematics
1 answer:
tatyana61 [14]2 years ago
8 0

Answer:

Paul = 30 pounds

Step-by-step explanation:

If Adam (A), Paul(P) and Jake(J) together they weigh 180 pounds (A+P+J=180); and Adam and Jake is 2:3 (2A=3J) then how much does paul weigh?

A+P+J=180, 2A=3J, J=60 we have; A=(3/2)J=(3/2)*60 → A=90, 90+P+60=180 →

P=180-90-60 → P=30

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Which graph shows the solution to the inequality Negative 3 x minus 7 less-than 20
Aleksandr-060686 [28]

Answer:

A number line goes from negative 10 to positive 10. An open circle appears at negative 9. The number line is shaded from negative 9 through positive 10.

Step-by-step explanation:

we have

-3x-7

Solve for x

Adds 7 both sides

-3x

-3x

Divide by -3 both sides

Remember that

When you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

so

x> 27/(-3)\\x>-9

The solution is the interval (-9,∞)

therefore

A number line goes from negative 10 to positive 10. An open circle appears at negative 9. The number line is shaded from negative 9 through positive 10.

6 0
2 years ago
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Hope researches the impact of one variable on another. She graphs the data from her research and sees that the data forms a shap
BigorU [14]

The <em><u>correct answer</u></em> is:

She can determine that while there is an association between the variables, there is no correlation, and she cannot determine causation.

Explanation:

Since there is an arch shape to her graph, we know that as one variable changes, the other changes in the same manner. This means there is an association between the variables.

However, since the graph is not linear, there is no correlation between the variables. Since there is no correlation, we cannot determine causation.

6 0
2 years ago
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Suppose that the IQs of university​ A's students can be described by a normal model with mean 140 and standard deviation 8 poi
AnnZ [28]

Answer:

0.0266, 0.9997,0.7856

Step-by-step explanation:

Given that the IQs of university​ A's students can be described by a normal model with mean 140 and standard deviation 8 points. Also suppose that IQs of students from university B can be described by a normal model with mean 120 and standard deviation 11. Let x be the score by A students and Y the score of B.

A)P(X>135) = \\P(Z>0.625)\\=0.0266

B) Since X and Y are independent we have

X-Y is Normal with mean = 140-120 =20 and Var (x-y)=Var(x)+Var(y) = 19

P(X-Y)>5\\\\=1-0.00029\\=0.9997

C) For a group of 3, average has std deviation = \frac{11}{\sqrt{3} } \\=6.351

P(\bar y >115)\\= P(z>\frac{-5}{6.351} \\=0.7856

3 0
2 years ago
Jinghua hiked 4 1/2 miles through the woods in 2 1/4 hours. She hiked the return trip at the same average rate but by a differen
Anna007 [38]

Answer:

5 miles.

Step-by-step explanation:

Consider the question: Jinghua hiked 4 1/2 miles through the woods in 2 1/4 hours. She hiked the return trip at the same average rate but by a different route taking 2 1/2 hours. How many miles did Jinghua hike on the return trip ?

First of all, we will find Jinghua's speed using given information as:

\text{Speed}=\frac{\text{Distance}}{\text{Time}}

Convert mixed fractions into improper fractions:

4\frac{1}{2}\Rightarrow \frac{9}{2}

2\frac{1}{4}\Rightarrow \frac{9}{4}

\text{Jinghua's speed}=\frac{\frac{9}{2}\text{ Miles}}{\frac{9}{4}\text{ Hours}}

Using property \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{ad}{bc}:

\text{Jinghua's speed}=\frac{9*4\text{ Miles}}{9*2\text{ Hours}}

\text{Jinghua's speed}=\frac{2\text{ Miles}}{\text{ Hour}}

We know that distance is equal to the product of speed and time.

\text{Distance}=\text{Speed}\times\text{Time}

Since we have been given that Jingua hiked the return trip at the same average rate, so distance covered by her on return trip would be speed (2 miles her hour) times given time (2 1/2 hours).

\text{Distance covered by Jingua on return trip}=\frac{2\text{ Miles}}{\text{ Hour}}\times 2\frac{1}{2}\text{ Hours}

\text{Distance covered by Jingua on return trip}=2\text{ Miles}\times \frac{5}{2}

\text{Distance covered by Jingua on return trip}=5\text{ Miles}

Therefore, Jingua hiked 5 miles on her return trip.

8 0
2 years ago
Which pair of expressions has equivalent values? 1 Superscript 13 and 1 Superscript 15 6 Superscript 1 and 9 Superscript 1 7 Sup
lora16 [44]

Answer:

1 Superscript 13 and 1 Superscript 15

Step-by-step explanation:

The process of exponentiation can be mathematically written as:

a^b

where a is called the base, and b is called the exponent.

Basically it means that we have to multiply the base with itself as many times as the value of the exponent.

For example 2^4 is 2•2•2•2

Having this in mind, 1^13 and 1^15 have equivalent values, because no matter how many times we multiply 1 with itself it will always be equal to 1.

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2 years ago
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