First, we need to find the area of the pond.
The formula for the area of a circle is: 3.14r^2
So, first of all, the radius is 10, and we need to square that, so 10 x 10 = 100.
There. Now, with the squared radius, we need to multiply that by pi.
100 x 3.14 = 314.
The area of the pond is 314 square meters.
Secondly, we need to find the number of frogs. If there are 2 frogs in each square meter, then 2 x 314 = 628.
There are 628 frogs in the pond.
3.6 customers x customers
-------------------- = ----------------
.5 hours 7.5 hours
using cross products
3.6 * 7.5 = x * .5
divide by .5 on each side
3.6 * 7.5 / .5 =x
54 =x
You can help 54 customers
Incomple question. However, here's the remaining part of the question:
14
2009
Meadow Fritillary= 5
Variegated Fritillary= 7
Zebra Swallowtail= 33
Eastern-Tailed Blue= 242
Louden County Butterfly Count
2010
Meadow Fritillary 34
Variegated Fritillary 95
Zebra Swallowtail 21
Eastern-Tailed Blue 168
2011
Meadow Fritillary
Variegated Fritillary
Zebra Swallowtail
Eastern-Tailed Blue
10
170
<u>Options</u>:
A) All butterfly populations are steadily decreasing.
B)All butterfly populations were larger than usual in 2010.
C)The Eastern-Tailed Blue butterfly is more common than the others.
D)The Meadow Fritillary is equally common as the Variegated Fritillary
Answer:
<u>C</u>
Step-by-step explanation:
Looking through the above count data by Louden County Wildlife Conservancy from 2009 to 2011 we notice the Eastern- Trailed Blue butterfly has a higher count, which implies that the Eastern-Tailed Blue butterfly is more common than the other butterflies.
Therefore, we could infer from the samples, that the Eastern-Tailed Blue butterfly is more common than others from the records of the past 3 three years.
Answer:
This is late, but for anyone else that needs it, it's B. 4x-5
