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lutik1710 [3]
2 years ago
13

Choose the correct statement. A. A​ firm's minimum efficient scale is the smallest quantity of output at which​ long-run average

cost reaches its lowest level. B. A​ firm's minimum efficient scale increases when the number of people employed increases. C. At outputs greater than the minimum efficient​ scale, a firm experiences economies of scale. D. At outputs less than the minimum efficient​ scale, a firm experiences diseconomies of scale.
Engineering
1 answer:
DENIUS [597]2 years ago
3 0

Answer:

Option B

Explanation:

For any company, the minimum efficient scale of production reflects the minimum of the average total cost for the firm the left to the organization experience economies of scale and to the right of it the industrial organisation faces economies of scale. A​ firm's minimum efficient scale increases when the number of people employed increases.

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A railcar with an overall mass of 78,000 kg traveling with a speed vi is approaching a barrier equipped with a bumper consisting
sergij07 [2.7K]

Answer:

v₀ = 2,562 m / s  = 9.2 km/h

Explanation:

To solve this problem let's use Newton's second law

              F = m a = m dv / dt = m dv / dx dx / dt = m dv / dx v

              F dx = m v dv

We replace and integrate

            -β ∫ x³ dx = m ∫ v dv

            β x⁴/ 4 = m v² / 2

We evaluate between the lower (initial) integration limits v = v₀, x = 0 and upper limit v = 0 x = x_max

        -β (0- x_max⁴) / 4 = ½ m (v₀²2 - 0)

         x_max⁴ = 2 m /β   v₀²

         

Let's look for the speed that the train can have for maximum compression

         x_max = 20 cm = 0.20 m

         

         v₀ =√(β/2m)   x_max²

Let's calculate

          v₀ = √(640 106/2 7.8 104)    0.20²

          v₀ = 64.05  0.04

          v₀ = 2,562 m / s

          v₀ = 2,562 m / s (1lm / 1000m) (3600s / 1h)

          v₀ = 9.2 km / h

5 0
2 years ago
A person puts a few apples into the freezer at -15oC to cool them quickly for guests who are about to arrive. Initially, the app
frosja888 [35]

Answer:

Temperature at center of apples = 11.2⁰C

Temperature at surface of apples = 2.7⁰C

Amount of Heat transferred = 17.2kJ

Explanation:

The properties of apple are given as:

k = 0.418 W/m.°C

ρ = 840 kg/m³

Cр = 3.81 kJ/kg.°C

α = 1.3*10 ⁻⁷ m²/s

h = 8 W/m².°C

d = 0.09m

r = 0.045m

t = 1 hour = 3600s

<h2>Solution</h2>

Biot number is given as:

Bi = \frac{hr}{k}= \frac{8\cdot0.045}{0.418}=0.861

The constants λ₁ and A₁ corresponding to Biot number (from the table) are:

λ₁ = 1.476

A₁ = 1.239

Fourier Number is:

T = \frac{a\cdot{t}}{r^2} = \frac{(1.3\cdot10^{-7})(3600)}{0.045^2}= 0.231> 0.2

As Fourier Number > 0.2 , one term approximates solutions are applicable

The temperature at the center of apples, The temperature at surface of apples and Amount of heat transfer is found in the ATTACHMENT.

8 0
2 years ago
A distância entre duas retas reversas é a medida de um segmento orientado que *?
Agata [3.3K]

Answer:

Fatec – SP) Seja A um ponto pertencente à reta r, contida no plano α. É verdade que:

a) existe uma única reta que é perpendicular à reta r no ponto A.

b) existe uma única reta, não contida no plano α, que é paralela à reta r.

c) existem infinitos planos distintos entre si, paralelos ao plano α, que contém a reta r.

d) existem infinitos planos distintos entre si, perpendiculares ao plano α e que contêm a reta r.

e) existem infinitas retas distintas entre si, contidas no plano α e que são paralelas à reta r.

2. (UF – AL) Classifique como verdadeira ou falsa cada uma das afirmativas abaixo.

1) Duas retas que não têm pontos com

8 0
2 years ago
A cylindrical drum (2 ft. dia ,3 ft height) is filled with a fluid whose density is 40 lb/ft^3. Determine (a. the total volume o
Ksivusya [100]

Answer:

a)V=9.42\ ft^3

b)Mass in lb = 376.8 lb

Mass in slug = 11.71 slug

c)v=0.025\ ft^3/lb

d)w=1276 \ lb/ft.s^2

Explanation:

Given that

d= 2 ft

r= 1 ft

h= 3 ft

Density

\rho = 40\ lb/ft^3

a)

We know that volume V given as

V=\pi r^2 h

V=\pi \times 1^2\times 3

V=9.42\ ft^3

b)

Mass = Density x volume

mass =40\times 9.42\ lb

mass= 376.8 lb

We know that

1 lb = 0.031 slug

So 376.8 lb= 11.71 slug

Mass in lb = 376.8 lb

Mass in slug = 11.71 slug

c)

we know that specific volume(v) is the inverse of density.

v=\dfrac{1}{\rho}\ ft^3/lb

v=\dfrac{1}{40}\ ft^3/lb

v=0.025\ ft^3/lb

d)

Specific weight(w) is the product of density and the gravity(g).

w= ρ X g

w = 40 x 31.9

w=1276 \ lb/ft.s^2

8 0
2 years ago
The extruder head in a fused- deposition modeling setup has a diameter of 1.25 mm (0.05 in) and produces layers that are 0.25mm
Angelina_Jolie [31]

Answer:

The time taken will be "1 hour 51 min". The further explanation is given below.

Explanation:

The given values are:

Number of required layers:

= \frac{38}{0.25}

= 152 \ layers

Diameter (d):

= 1.25 mm

Velocity (v):

= 40 mm/s

Now,

The area of one layer will be:

= 38\times 38 \ mm^2

= 1444 \ mm^2

The area covered every \second will be:

= d\times v

= 1.25\times 40

= 50 \ mm^2

The time required to deposit one layer will be:

= \frac{1444}{50}

= 28.88 \ sec

The time required for one layer will be:

= 15 \ sec

∴ Total times required for one layer will be:

= 15+28.88

= 43.88 \ sec

So,

Number of layers = 152

Therefore,

Total time will be:

= 152\times 43.88

= 6669.76 \ sec

= 1 \ hour \ 51 \ min

6 0
2 years ago
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