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1 year ago

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The price of a bike at Store A is 5/6 the price x (in dollars) at Store B. The price at Store A is $150.60. Write and solve an e

quation to find how much you save by buying the bike at Store A.

2 answers:

notsponge [240]1 year ago

7 0

Let

x------> the price of a bike in Store B

y------> the price of a bike in Store A

we know that

$y=\frac{5}{6}x$ ------> equation A

$y=\$150.60$

Substitute the value of y in equation A

$150.60=\frac{5}{6}x$

Solve for x

Multiply by $\frac{6}{5}$ both sides

$x=\frac{6}{5}*150.60\\\\x=\$180.72$

Find the difference of the price Store B and Store A

$\$180.72-\$150.60=\$30.12$

therefore

<u>the answer is</u>

$\$30.12$

Marina CMI [18]1 year ago

3 0

Let the price in storeB=x
5/6x=150.6
x=180.72
180.72-150.6=$30.12
you save $30.12

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Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =

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Here is the question attached with.

$m\angle CEA =90 \ (deg)$

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Options $1,4,5,6$ are correct answers.

Step-by-step explanation:

⇒As $\ ray\ AE$ is ⊥ $FEC$ so it will forms right angled triangle then $m\angle CEA =90\ (deg)$ .

⇒Measure of $\angle BEF =135\ (deg)$ as $\angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg)$ as $\angle AEB$ is the bisector of $\angle AEC$ ,meaning that $\angle AEB$ is half of $\angle AEC$ so $\angle AEB = 45\ (deg)$ .

⇒ $\angle CEF$ is a straight line as the angles measure over it is $180\ (deg)$ .

⇒Measure of $\angle AEF = 90\ (deg)$ from linear pair concept.

As $\angle CEA + \angle AEF = 180\ (deg)$ ,plugging the values of $m\angle CEA =90\ (deg)$ we have $\angle AEF = 90\ (deg)$ .

The other two options are false as:

$m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225$

it is exceeding $180\ (deg)$ whereas $\angle CEF$ is a

straight line.

And $m\angle CEB=2(m\angle CEA)$ is not true.

As $\angle CEA = 90\ (deg)$ and $\angle CEB=45\ (deg)$

So we have total $4$ answers.

The correct options are $1,4,5,6$ .

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