Two <em>possible answers</em> are:
23.65 and 23.72.
Explanation:
For the first number, 23.65, we are rounding to the tenths place. 23.65 itself is smaller than 23.7. Looking behind the tenths place, the digit behind it is 5. This means we round the tenths place up; this becomes 23.7.
23.72 is larger than 23.7. We will round it to the tenths place as well. Looking behind the tenths place, we have a 2; this means we "round down." This means leave the 7 as it is and drop the other digits behind it. This gives us 23.7.
Use the formula A = p( 1 + x)^n.
A = 1831.84(1 + 0.14)^6
You can finish.
The word problem gives you the information you need to solve it.
5 batches of chili were made using 63.5 kg of beans total. You can assume the same amount of beans were used in each of the 5 batches, so ...
your equation would be:
63.5 ÷ 5 = # of beans in each batch.
63.5 ÷ 5 = 12.7
12.7 kg of beans were used in each of the 5 batches.
Check step:
12.7 × 5 = 63.5
Answer:
Mass of gold bar = 13.896 kg
Step-by-step explanation:
Volume of gold bar = Area of trapezium x Length of bar
Length of bar = 16 cm
Area of trapezium = 2 x Area of triangle + Area of rectangle
Area of triangle = 0.5 x 5 x 3 = 7.5 cm²
2 x Area of triangle = 2 x 7.5 = 15 cm²
Area of rectangle = 6 x 5 = 30 cm²
Area of trapezium = 15 + 30 = 45 cm²
Volume of gold bar = 45 x 16 = 720 cm³
Density of gold = 19.3 g/cm³
Mass of gold bar = 720 x 19.3 = 13896 g = 13.896 kg
Mass of gold bar = 13.896 kg
Step-by-step explanation:
Start by writing 492,623 in standard form
4 hundred thousands + 9 ten thousands + 2 thousands + 6 hundreds + 2 tens + 3 ones
We can write this in other ways by moving a digit to the next smaller place value. For example, we move the 4 one place to the right to get 49 ten thousands:
49 ten thousands + 2 thousands + 6 hundreds + 2 tens + 3 ones
Then, we can move the 49 ten thousands to the right to get 492 thousands, and we can move 6 hundreds to the right to get 62 tens.
492 thousands + 62 tens + 3 ones
Or, we can do this:
4926 hundreds + 23 ones
centimeter long.