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2 years ago

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A decimal number changed to 23.7 after it was rounded. Give a decimal number that is less than 23.7 and another that is greater

than 23.7 that the each round to 23.7.explain to what place each number was rounded

2 answers:

nika2105 [10]2 years ago

7 0

23.74 would round down to 23.7 because 4 is less than 5.

23.69 would round up to 23.7 because 9 is higher than 5.

mrs_skeptik [129]2 years ago

3 0

Two <em>possible answers</em> are:

23.65 and 23.72.

Explanation:

For the first number, 23.65, we are rounding to the tenths place. 23.65 itself is smaller than 23.7. Looking behind the tenths place, the digit behind it is 5. This means we round the tenths place up; this becomes 23.7.

23.72 is larger than 23.7. We will round it to the tenths place as well. Looking behind the tenths place, we have a 2; this means we "round down." This means leave the 7 as it is and drop the other digits behind it. This gives us 23.7.

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A computer manufacturer ships laptop computers with the batteries fully charged so that customers can begin to use their purchas

Nataly_w [17]

Answer:

The p value obtained and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidenc to reject the null hypothesis, and we can said that at 5% of significance the proportion of new laptop's with fully charge for the new model is significantly higher compared to the old model.

Step-by-step explanation:

1) Data given and notation n

n=100 represent the random sample taken

X=96 represent the laptop's arrived with fully charged batteries.

$\hat p=\frac{96}{100}=0.96$ estimated proportion of laptop's arrived with fully charged batteries.

$p_o=0.85$ is the value that we want to test

$\alpha=0.05$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the new model’s rate is at least as high as the previous model.:

Null hypothesis: $p \leq 0.85$

Alternative hypothesis: $p > 0.85$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.96 -0.85}{\sqrt{\frac{0.85(1-0.85)}{100}}}=3.08$

4) Statistical decision

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level is not provided, but we can assume $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a one side test the p value would be:

$p_v =P(z>3.08)=0.0010$

So based on the p value obtained and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidenc to reject the null hypothesis, and we can said that at 5% of significance the proportion of new laptop's with fully charge for the new model is significantly higher compared to the old model.

4 0

2 years ago

Please see attachment for the question.

nekit [7.7K]

Answer:

$\frac{ {20x}^{3} - {7x}^{2} + 3x - 7 }{ { - 13x}^{2} - 5}$

-13x²-5≠0

13x²+5≠0

x²≠ -5/13

option D

8 0

2 years ago

Read 2 more answers

A region in the plane is bounded by the graph of y=1/x, the x-axis, the line x=m and the line x=3m, m>0. the area of this reg

raketka [301]

The correct option is a): "i<span>s independent of m</span>".

By the fundamental theorem of calculus:<span><span>A′</span>(m)=<span>1<span>3m</span></span>⋅3−<span>1m
</span> =0</span> So the area doesn't change with respect to m.

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2 years ago

Read 2 more answers

An certain brand of upright freezer is available in three different rated capacities: 16 ft3, 18 ft3, and 20 ft3. Let X = the ra

ruslelena [56]

Answer:

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

$E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6=349.2$

$V(X) = E(X^2)-[E(X)]^2=349.2-(18.6)^2=3.24$

The expected price paid by the next customer to buy a freezer is $466

Step-by-step explanation:

From the information given we know the probability mass function (pmf) of random variable X.

$\left|\begin{array}{c|ccc}x&16&18&20\\p(x)&0.3&0.1&0.6\end{array}\right|$

<em>Point a:</em>

The Expected value or the mean value of X with set of possible values D, denoted by <em>E(X)</em> or <em>μ </em>is

$E(X) = $\sum_{x\in D} x\cdot p(x)$

Therefore

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

If the random variable X has a set of possible values D and a probability mass function, then the expected value of any function h(X), denoted by <em>E[h(X)]</em> is computed by

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)$

So $h(X) = X^2$ and

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)\\E[X^2]=$\sum_{D}x^2\cdot p(x)\\ E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6\\E(X^2)=349.2$

The variance of X, denoted by V(X), is

$V(X) = $\sum_{D}E[(X-\mu)^2]=E(X^2)-[E(X)]^2$

Therefore

$V(X) = E(X^2)-[E(X)]^2\\V(X)=349.2-(18.6)^2\\V(X)=3.24$

<em>Point b:</em>

We know that the price of a freezer having capacity X is 60X − 650, to find the expected price paid by the next customer to buy a freezer you need to:

From the rules of expected value this proposition is true:

$E(aX+b)=a\cdot E(x)+b$

We have a = 60, b = -650, and <em>E(X)</em> = 18.6. Therefore

The expected price paid by the next customer is

$60\cdot E(X)-650=60\cdot 18.6-650=466$

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2 years ago

. A conductor with a diameter of 100 mils has an area of

Zielflug [23.3K]

In order to answer the question, you need to know the area of a circle.
Area = pi * r^2
Area = 3.14 * (100/2) ^ 2
Area = 3.14 * 50^2
Area = 7850 mils^2 = 0.00785 in^2

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2 years ago