Question

Which of the following is equivalent to log StartFraction one-ninth over k EndFraction?

Answer 1

Answer:

The given expression is equal to,

$\log (\frac{1}{9}) - \log k$

Step-by-step explanation:

we are to find the expression equivalent to,

$\log (\frac {\frac {1}{9}}{k})$

which is equal to,

$\log (\frac{1}{9}) - \log k$

Since, we know that,

$\log (\frac {m}{n})$

= $\log(m) - \log(n)$

where all the terms  are defined.

Answer 2

Answer:

The answer is A on edg. 2020

Step-by-step explanation: